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Whitepunk [10]
3 years ago
15

Two carts have a compressed spring between them and are initially at rest. One of the carts has total mass, including its conten

ts, of 5.0 kg, and the other has total mass of 3.0 kg. If the 3.0 kg cart is moving at 3.0 m/s after the spring is allowed to push the carts apart, what is the velocity of the 5.0 kg cart after release? The system is closed.A) -1.8 m/s B) -5.0 m/sC) -0.56 m/sD) -0.0 m/s
Physics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

A) - 1.8 m/s

Explanation:

As we know that whole system is initially at rest and there is no external force on this system

So total momentum of the system must be conserved

so we will have

m_1v_1 + m_2v_2 = 0

now plug in all data into above equation

5(v) + 3(3)

5v = -9

v = -1.8 m/s

so correct answer is

A) - 1.8 m/s

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How many moles of He atoms are in 6.00 g of He?
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Explanation:

9.5

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You step onto a hot beach with your bare feet. A generated in your foot, travels through your nervous system at an average speed
madreJ [45]

Answer: 12.44 millisecond

Explanation:

Based on the information given, to know the time taken for the impulse, which travels a distance of 1.58m to reach the brain will be:

Time taken = Distance/Speed

Time taken = 1.58/127

Time taken = 0.01244

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3 years ago
The microwaves in a microwave oven are produced in a special tube called a magnetron. The electrons orbit the magnetic field at
Rama09 [41]

Answer:

<em>The magnetic field is 0.0857 T.</em>

Explanation:

The electrons orbit the magnetic field with a centripetal force equal to

F = \frac{mv^{2} }{r}

also, the force on an electron in a magnetic field is gotten as

F = Bqv

equating this two equations give

\frac{mv^{2} }{r} = Bqv

mv/r = Bq

where m is the mass of the electron = 9.11 x 10^-31 kg

v is the the linear speed of the electron

B is the magnetic field on the electron

r is the radius of the orbital movement

q is the charge on an electron = 1.602 x 10^-19 C

but, the linear speed v = ωr

where ω is the angular speed of the electron

substituting into equation above, we have

mωr/r = Bq

which reduces to

mω = Bq

finally, w know that the angular speed is related to the frequency of the electron by

ω = 2πf

we then finally have

2mπf = Bq

where f is the frequency emitted by the electron = 2.4 GHz = 2.4 x 10^9 Hz

substituting values into the equation, we have

2 x 9.11 x 10^-31 x 3.142 x 2.4 x 10^9 = B x 1.602 x 10^-19

B = (1.3734 x 10^-20)/(1.602 x 10^-19) = <em>0.0857 T</em>

= <em>85.7 mT</em>

7 0
3 years ago
Suppose you take a trip that covers 180 km and takes 3 hours to make.
Allushta [10]

Answer:

v = 16,66 m/s

Explanation:

To obtain the velocity of the train we must use the velocity formula for a uniform line movement:

v = x/t

Where x is the space and t is time.

replacing given values:

v = 180 km / 3 h

v = 60 km/h

to pass this value to international units:

v = 60 / 3,6 m/s

v = 16,66 m/s

5 0
3 years ago
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