Answer:
reading would be 5.413 m.
Explanation:
Given:-
- The actual distance from ruler to an object is d = 24.0 m
- The adiabatic bulk modulus, B = 2.37 *10^9 Pa
- The density of seawater, ρ = 1025 kg/m^3
- The preset value of speed of sound in air, v_th = 343 m/s.
Find:-
Determine the distance reading that the ruler displays.
Solution:-
- We will first determine the actual speed of the sound ( v_a) in sea-water which can be determined from the following formula:
v_a = √ (B / ρ )
- Plug in the values in the relationship above and compute v_a:
v_a = √ ( 2.37 *10^9 / 1025 )
v_a = 1520.59038 m/s
- The time taken (t) for for the sound to travel from source(ruler) to an object which is d distance away.
d = v_a*t
t = d / v_a
t = 24.0 / 1520.59038
t = 0.01578 s
- The distance reading on the ruler would be preset speed (v_th) of sound in air multiplied by the time taken(t).
reading = v_th*t
reading = (343)*(0.01578)
= 5.413 m
Answer:
The pressure in the chamber are of p= 0.127 atm.
Explanation:
n= 2.5 moles
T= 310 K
V= 0.5 m³ = 500 L
R= 0.08205746 atm. L /mol . K
p= n*R*T/V
p= 0.127 atm
Answer:
B
Explanation:
D is nonsense. The current keeps coming through all lights.
A is wrong. The exact opposite happens. More bulbs more resistance.
C is wrong. More resistance less current, not more.
So your answer is B because the voltage drop in each decreases when there are more bulbs.
Answer:
Sub stratul exterior lichid-metal al miezului Pământului se află o bilă solidă de fier și aliaj de nichel cu aproximativ 1,60 km în diametru.
Explanation:
