Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
Well I'm assuming that you want me to simplify the fraction 40/6. Since 40 can go into 6 multiple times, this fraction is going to be a mixed number.
40/6 in simplest form is 6 2/3. Hope I helped!
Answer:
B
Step-by-step explanation:
The answer is b because the domain of anything is always x or on the x axis .
Answer:
The answer is "Option C"
Step-by-step explanation:
The choices were missing in the question, which is defined in the attached file please find it.
To attend university, Chole should pay the cost of a room and board each semester. Even though the Chole will not be in college, she will still have a room as well as a board and continue living.
- If she will not attend college, it also has to equate rooms and board costs per six months since increase towards the room or board charges.
- If there's an increase in rooms and boarding costs because she did not understand below the rise in their school fees, therefore the financial cost reduces that desire of she attend.
1.4/7 in simplest form is 0.2/1 because you divide each side by 7.