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3 years ago

14

How would the addition of protons affect the concentration of CH3COOH? How would the addition of OH– affect the amount of CH3COO

H present? How would the addition of CH3COO– affect the concentration of protons? What would happen to [H+] if [CH3COOH] were increased?

2 answers:

Deffense [45]3 years ago

8 0

Answer:

1) increase concentration

2) decrease the amount

3) decrease the concentration

4) it would increase

Explanation: edge 2021

fiasKO [112]3 years ago

7 0

Answer:

1) increase concentration

2) decrease the amount

3) decrease the concentration

4) it would increase

Explanation:

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Which of the following is a chemical property of a sheet of paper?

Tomtit [17]

Answer:

A

Explanation:

Flammability is a chemical property. The paper crumbling would be a physical property. The inability to attract a magnet or conduct electricity would be considered electrical properties

3 0

3 years ago

A hair spray can has a volume of 565 mL. If the can is at 42 C and 5 atm, what volume would the hair spray occupy at STP?

Alex777 [14]

Answer:

$V_2 = 2.447$ atm

Explanation:

As we know that

$PV = nRT\\$

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin

R is the gas constant $R = 0.08206$

V is the volume in liters

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

Substituting the given values in above equation, we get -

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\\frac{5*0.565}{315.15} = \frac{1*V_2}{273}$

On rearranging, we get

$\frac{5*0.565*273}{315.15} = V_2\\V_2 = 2.447$

$V_2 = 2.447$ atm

5 0

3 years ago

How many mL of a 1.63 M solution would contain 12 g of Na(OH)?

Evgesh-ka [11]

Answer:

89 mL of solution would contain the given amount of Al(NO₃)₃.

Explanation:

Hope this help

5 0

3 years ago

A 25.0g tin sample was placed in boiling water at 99.5 C until it had the same temperature. Afterwards, the tin sample was place

MrMuchimi

Answer : The specific heat of tin is, 0.213 J/g.K

Explanation :

Formula used :

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = amount of heat lost = -399.4 J

c = specific heat capacity of tin = ?

m = mass of tin = 25.0 g

$T_{final}$ = final temperature = $24.5^oC=273+24.5=297.5K$

$T_{initial}$ = initial temperature = $99.5^oC=273+99.5=372.5K$

Now put all the given values in the above formula, we get:

$-399.4J=25.0g\times c\times (297.5-372.5)K$

$c=0.213J/g.K$

Therefore, the specific heat of tin is, 0.213 J/g.K

7 0

3 years ago

How many molecules are there in 6.07g of Ag2CO3

Mice21 [21]

There are $1.3244 \times 10^{22}$ molecules in 6.07 grams of silver carbonate.

Explanation:

Moles of a compound is defined as ratio of mass of the compound to the molar mass of the compound.

$Moles(n)=\frac{\text{Mass of the compound}(m)}{\text{Molar mass of the compound}(M)}$

1 mole corresponds to $N_A$ numbers of atoms or molecules or ions.

1 mole = $N_A$

$N_A$ = Avogadro number = $6.022 times 10^{23}$ atoms, molecules/ions

Number of molecules particles in 'n' moles of compound:N

$N = n\times N_A$

Mass of silver carbonate,m = 6.07 g

Molar mass of carbonate ,M= 276 g/mol

Moles of silver carbonate = n

$n=\frac{m}{M}=\frac{6.07 g}{276 g/mol}=0.02199 mol$

Number of molecules of silver carbonate in 0.02199 moles.

$N=n\times N_A=0.02199 mol\times 6.022 times 10^{23}=1.3244 \times 10^{22} molecules$

There are $1.3244 \times 10^{22}$ molecules in 6.07 grams of silver carbonate.

4 0

4 years ago