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nadezda [96]
4 years ago
5

In the reaction, HCl + H2O produces H3O + Cl, what is the conjugate acid

Chemistry
1 answer:
Olenka [21]4 years ago
8 0

Answer:

Conjugate acid is H3O

Explanation:

HCl + H2O = H3O + Cl

HCl = H+ and Cl- = Acid

H2O = OH- and H+ = Neutral as equal OH- and H+

H3O = H3O+ = Acid also known as Hydronium

Cl = Just free floating Chlorine = Cl-

Conjugate acid is H3O

Acid = A solution with more H+ ions than OH- ions.

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Calculate the change in entropy when 10.0 g of CO2 isothermally expands from a volume of 6.15 L to 11.5 L. Assume that the gas b
USPshnik [31]

Answer:

The change in entropy of the carbon dioxide is 1.183\times 10^{-3} kilojoules per Kelvin.

Explanation:

By assuming that carbon dioxide behaves ideally, the change in entropy (\Delta S), measured in kilojoules per Kelvin, is defined by the following expression:

\Delta S = m\cdot \bar c_{v}\cdot \ln \frac{T_{f}}{T_{o}}+m\cdot \frac{R_{u}}{M}\cdot \ln \frac{V_{f}}{V_{o}} (1)

Where:

m - Mass of the gas, measured in kilograms.

\bar c_{v} - Isochoric specific heat of the gas, measured in kilojoules per kilogram-Kelvin.

T_{o}, T_{f} - Initial and final temperatures of the gas, measured in Kelvin.

V_{o}, V_{f} - Initial and final volumes of the gas, measured in liters.

R_{u} - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.

M - Molar mass, measured in kilograms per kilomole.

If we know that T_{o} = T_{f}, m = 0.010\,kg, R_{u} = 8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K}, M = 44.010\,\frac{kg}{kmol}, V_{o} = 6.15\,L and V_{f} = 11.5\,L, then the change in entropy of the carbon dioxide is:

\Delta S = \left[\frac{ (0.010\,kg)\cdot \left(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)}{44.010\,\frac{kg}{kmol} } \right]\cdot \ln \left(\frac{11.5\,L}{6.15\,L}\right)

\Delta S = 1.183\times 10^{-3}\,\frac{kJ}{K}

The change in entropy of the carbon dioxide is 1.183\times 10^{-3} kilojoules per Kelvin.

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Answer:

the answer is 4

Explanation:

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3 years ago
Which is the most prevalent species in a 0.25 m aqueous solution of phosphoric acid h3po4 g?
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Answer is: H₃PO₄.

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<span> First step: H</span>₃PO₄(aq) ⇄ H₂PO₄⁻(aq) + H⁺(aq).<span>
Second step: H</span>₂PO₄⁻(aq)⇄ HPO₄²⁻(aq) + H⁺(aq).<span>
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3 years ago
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alexandr402 [8]

The question is incomplete, the complete question is;

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II) sulfate PbSO₄ is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode.

Suppose a current of 96.0 A is fed into a car battery for 37.0 seconds. Calculate the mass of lead deposited on the cathode of the battery. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

Answer:

3.81 g of lead

Explanation:

The equation of the reaction is;

Pb^2+(aq) + 2e ---->Pb(s)

Quantity of charge = 96.0 A * 37.0 seconds = 3552 C

Now we have that 1F = 96500 C so;

207 g of lead is deposited by 2 * 96500 C

x g of lead is deposited by 3552 C

x = 207 *  3552/2 * 96500

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x = 3.81 g of lead

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