Question

A compound is found to have 55.7% hafnium+and+44.3%+chlorine.+what+is+the+empirical+formula?

Answer 1

The empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

How to calculate empirical formula?

The empirical formula of a compound is a notation indicating the ratios of the various elements present in a compound, without regard to the actual numbers.

The empirical formula of the given compound can be calculated as follows:

• Hafnium = 55.7% = 55.7g
• Chlorine = 44.3% = 44.3g

First, we convert mass values to moles by dividing by the molar mass of each element

• Hafnium = 55.7g ÷ 178.49g/mol = 0.312mol
• Chlorine = 44.3g ÷ 35.5g/mol = 1.25mol

Next, we divide each mole value by the smallest

• Hafnium = 0.312 ÷ 0.312 = 1
• Chlorine = 1.25 ÷ 0.312 = 4

Therefore, the empirical formula of a compound found to have 55.7% hafnium and 44.3% chlorine is HfCl4.

Learn more about empirical formula at: brainly.com/question/14044066

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