It depends on the unit though if its in miles per hour then you can simply divide 50 by 2
Answer:
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Analytical Chemistry 2.1 (Harvey)
2: Basic Tools of Analytical Chemistry
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2.5: Preparing Solutions
Last updatedAug 10, 2020
2.4: Basic Equipment
2.6: Spreadsheets and Computational Software
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Contributed by David Harvey
Professor (Chemistry and Biochemistry) at DePauw University
Preparing a solution of known concentration is perhaps the most common activity in any analytical lab. The method for measuring out the solute and the solvent depend on the desired concentration and how exact the solution’s concentration needs to be known. Pipets and volumetric flasks are used when we need to know a solution’s exact concentration; graduated cylinders, beakers, and/or reagent bottles suffice when a concentrations need only be approximate. Two methods for preparing solutions are described in this section.
Answer:
you know that they will be a displacement reaction that will form a barium salt:
Ba(NO3)2+ 2NaCl--> BaCl2 + 2NaNO3
So now that we have that formula and the molecular weight we can determine how much salt will be made. So here we convert the grams to moles
(42.3g Ba(NO3)2)*(1 mole/261.34g) = 0.16185 mol
In the molecular formula we know that 1 mole of Barium nitrate will create 1 mole of Barium chloride, so in this case (in a perfect world) you should get 0.16185 mole of barium chloride (208.23 g/mol) that we then have to convert to grams.
(0.16185 mol BaCl2) * ( 208.23 g/mol) = 33.7037 g of Barium Chloride (rounded to 3 significant digits = 33.7g)
Answer: 344.927778
Work: T(k)=(T(°F)+459.67)x5/9
T(K)=(60°F+459.67)x5/9=288.71 K
