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3 years ago

Which law describes what happens when two skaters push apart in a rink? (Newton’s laws)

Physics

1 answer:

Nat2105 [25]3 years ago

7 0

Answer:

Newton's third law

Explanation:

Newton's Third Law of equal and opposite forces is very important when considering collisions between objects or propulsion. In these situations, all of the forces are internal, which means that for every force, there will be an equally sized force in the opposite direction. An example is two skaters out on the ice.

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Calculate the energy, wavelength, and frequency of the emitted photon when an electron moves from an energy level of -3.40 eV to

jasenka [17]

Answer:

(a) The energy of the photon is 1.632 x $10^{-8}$ J.

(b) The wavelength of the photon is 1.2 x $10^{-17}$ m.

Explanation:

Let;

$E_{1}$ = -13.60 ev

$E_{2}$ = -3.40 ev

(a) Energy of the emitted photon can be determined as;

$E_{2}$ - $E_{1}$ = -3.40 - (-13.60)

= -3.40 + 13.60

= 10.20 eV

= 10.20(1.6 x $10^{-9}$ )

$E_{2}$ - $E_{1}$ = 1.632 x $10^{-8}$ Joules

The energy of the emitted photon is 10.20 eV (or 1.632 x $10^{-8}$ Joules).

(b) The wavelength, λ, can be determined as;

E = (hc)/ λ

where: E is the energy of the photon, h is the Planck's constant (6.6 x $10^{-34}$ Js), c is the speed of light (3 x $10^{8}$ m/s) and λ is the wavelength.

10.20(1.6 x $10^{-9}$ ) = (6.6 x $10^{-34}$ * 3 x $10^{8}$ )/ λ

λ = $\frac{1.98*10^{-25} }{1.632*10^{-8} }$

= 1.213 x $10^{-17}$

Wavelength of the photon is 1.2 x $10^{-17}$ m.

E = hf

where f is the frequency of the photon.

1.632 x $10^{-8}$ = 6.6 x $10^{-34}$ x f

f = $\frac{1.632*10^{-8} }{6.6*10^{-34} }$

= 2.47 x $10^{25}$ Hz

Frequency of the emitted photon is 2.47 x $10^{25}$ Hz.

6 0

3 years ago

Please help asap. I'm terrible with atoms

11Alexandr11 [23.1K]

<span>Correct answer: more, smaller</span>

6 0

3 years ago

Read 2 more answers

Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the

KengaRu [80]

Answer:

V = -1.33 m/s

Explanation:

Given,

The mass of the camper, m = 100 kg

The velocity of the camper, v = 3.0 m/s

The combined mass of canoe and another camper, M = 225 kg

The velocity of the combined canoe and another camper, V = ?

According to the law of conservation of momentum,

MV + mv = 0 (Since the initial momentum of the dock is 0)

V = -mv/M

= -100 x 3/225

= -1.33 m/s

The negative sign indicates that the combined objects moves opposite to that of the camper.

Hence, the velocity of the combined canoe and camper is, V = -1.33 m/s

6 0

4 years ago

Can you come up with a mathematical relationship, based on your data that shows the relationship between distance from the charg

zalisa [80]

Answer:

Explanation:

This question appears incomplete because of the absence of the data been talked about in the question. However, there is a general ruling here and it can be applied to the data at hand.

If an increase in the distance of charges (let's denote with "d") causes the electric field strength (let's denote with"E") to increase, then the mathematical representation can be illustrated as d ∝ E (meaning distance of charge is directly proportional to electric field strength).

But if an increase in the distance of the charges causes the electric field strength to decrease, then the mathematical representation can be illustrated as d ∝ 1/E (meaning distance of charge is inversely proportional to electric field strength).

A scatterplot can also be used to determine this. If there is a positive correlation (correlation value is greater than zero but less than or equal to 1) on the graph, then it is illustrated as "d ∝ E" BUT if there is a negative correlation (correlation value is less than zero but greater than or equal to -1), then it can be illustrated as "d ∝ 1/E".

4 0

3 years ago

What does the variable p stand for in physics?

LUCKY_DIMON [66]

Is this a complete question or is there a problem to match it? maybe goggle it?

6 0

4 years ago