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Alexandra [31]
3 years ago
5

How do scientists describe force? why?

Physics
2 answers:
Alex17521 [72]3 years ago
8 0
A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.
Leona [35]3 years ago
8 0

Answer:

In science, force is the push or pull on an object with mass that causes it to change velocity (to accelerate). Force represents as a vector, which means it has both magnitude and direction. In equations and diagrams, a force is usually denoted by the symbol F.

We can't see it, but we can feel it (e.g. like wind)

Hope this helps :)

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rosijanka [135]

Answer:

A. I = V / R = 12 / 252 = .048 amps

V = I * R = .048 * 252 = 12 V

V is also the reading the voltage across the battery (12 Volts)

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Yuliya22 [10]
As wavelength increase, frequency decrease
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3 years ago
A 20000 kg subway train initially traveling at 18.5 m/s slows to a stop in a station and then stays there long enough for its br
hodyreva [135]

Answer:

rise the air temperature is 0.179241 K

Explanation:

Given data

mass = 20000 kg

velocity  = 18.5 m/s

long = 65 m

wide = 20 m

height = 12 m

density of the air = 1.20 kg/ m³

specific heat = 1020 J/(kg*K)

to find out

how much does the air temperature in the station rise

solution

we know here Energy lost by the train that is calculated by  

loss in the kinetic energy that is = 1/2 m v²

loss in the kinetic energy = 0.5 × 20000 ×18.5²

loss in the kinetic energy  is 3422500 J

and

this energy is used here to rise the air temperature that is KE / ( specific hat × mass )

so here  

air volume = 65 ×20×12

air volume = 15600 m³

air mass  =  ρ × V = 1.2 × 15600

air mass = 18720 kg

so

rise the air temperature = 3422500 / ( 1020 × 18720)

rise the air temperature is 0.179241 K

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4 years ago
A go-cart and rider have a mass of 100 kg. If the cart accelerates at 5 m/s2 during a 25 m sprint, how much work did the cart do
Murljashka [212]

Answer:20watts

Explanation:

6 0
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Read 2 more answers
Io and Europa are two of Jupiter's many moons. The mean distance of Europa from Jupiter is about twice as far as that for Io and
Anastaziya [24]

The universal gravitation law and Newton's second law allow us to find that the answer for the relation of the rotation periods of the satellites is:

        \frac{T_{Eu}}{T_{Io}} = 2.83

The universal gravitation law states that the force between two bodies is proportional to their masses and inversely proportional to their distance squared

           F = G  \frac{Mm}{r^2}

Where G is the universal gravitational constant (G = 6.67 10⁻¹¹ \frac{N m^2 }{kg^2}), F the force, m and m the masses of the bodies and r the distance between them

Newton's second law states that force is proportional to the mass and acceleration of bodies

          F = m a

Where F is the force, m the mass and the acceleration

In this case the body is the satellites of Jupiter and the planet,

            G \frac{Mm}{r^2} = m a

Suppose the motion of the satellites is circular, then the acceleration is centripetal

           a = \frac{v^2}{r}r

Where v is the speed of the satellite and r the distance to the center of the planet

     

we substitute

      G \frac{Mm}{r^2} = m \frac{v^2}{r}  \\G \frac{M}{r}  = v^2

Since the speed is constant, we can use the uniform motion ratio

      v = \frac{\Delta x}{t}

In the case of a complete orbit, the time is called the period.

The distance traveled is the length of the orbit circle

           Δx = 2π r

We substitute

           G \frac{M}{r} = (\frac{2 \pi  r}{T} )^2 \\T^2 = (\frac{4 \pi ^2}{GM}) \ r^3

           

Let's write this expression for each satellite

Io satellite

Let's call the distance from Jupiter is  

            r = r_{Io}  

           T_{Io}^2 = (\frac{4 \pi ^2}{GM} ) \ r_{Io}^3TIo² = (4pi² / GM) rIo³

Europe satellite

Distance from Jupiter  is

         r_{Eu} = 2 \ r_{Io}

We calculate

         T_{Eu} = ( \frac{4\pi ^2 }{GM} (2 \ r_{Io})^3\\T_{Eu} = ( \frac{4 \pi ^2 }{GM}) r_{Io} \ 8

         

         T_{Eu}^2 = 8 T_{Io}^2            

         

         \frac{ T_{Eu}}{T_{Io}} = \sqrt{8}  = 2.83

           

In conclusion, using the universal gravitation law and Newton's second law, we find that the answer for the relationship of the relation periods of the satellites is:

        \frac{T_{Eu}}{T_{Io}} = 2.83

Learn more about universal gravitation law and Newton's second law here:

brainly.com/question/10693965

6 0
3 years ago
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