To solve this, we use the z test.
The formula:
z = (x – u) / s
where x is sample value = 20, u is the mean = 15, and s is
the standard deviation = 2.5
z = (20 – 15) / 2.5
z = 2
Since we are looking for values greater than 20, this is
right tailed test. We use the standard distribution tables to find for P.
P = 0.0228
Therefore:
number of students = 100 * 0.0228 = 2.28
<span>2 to 3 students will get greater than 20 measurement</span>
Answer:
x = 6
Step-by-step explanation:
If A, B and C lies on a straight line in order, then;
AB+BC = AC
x+12+2x-4 = 26
x+2x+12-4 =26
3x+8 = 26
3x = 26-8
3x = 18
x = 18/3
x = 6
Hence the value of x is 6
Answer: (13.4996, 32.5004)
Step-by-step explanation:
The confidence interval for mean difference is given by :-
,
where 
= sample mean difference .
= critical t value (two-tailed)
SE= Standard error.
Given : 
SE= 4.2
Now, the confidence interval for mean difference will be :-
Hence, the required confidence interval : (13.4996, 32.5004)
9/4 = 2 1/4
1/4 = 0.25
2.25 is your answer
hope this helps
Answer:
35 in binary is 100011.
Step-by-step explanation:
To find decimal to binary equivalent, divide 35 successively by 2 until the quotient becomes 0.
