To count the number of valence electrons we look at the electronic configuration and add the electrons form the electronic shell with the highest principal quantum number.

Rb: [Kr] 5s¹ - 1 valence electron

Xe: [Kr] 5s² 4d¹⁰ 5p⁶ - 8 valence electrons

Sb: [Kr] 5s² 4d¹⁰ 5p³ - 5 valence electrons

I: [Kr] 5s² 4d¹⁰ 5p⁵ - 7 valence electrons

In: [Kr] 5s² 4d¹⁰ 5p¹ - 3 valence electrons

Rank from most to fewest valence electrons:

Xe > I > Sb > In > Rb

6 0

3 years ago

Read 2 more answers

(5 points)

ExtremeBDS [4]

Answer 2 : The given electronic configuration for a neutral atom of phosphorous in its ground state is incorrect.

Explanation :

A neutral atom of phosphorous has 15 electrons.

The given electronic configuration is incorrect.

The reason is, According to Aufbau principle, the electrons will be first filled in the sub-shell having lower orbital energy. As from the given configuration, 3p sub-shell has lower orbital energy than 4s sub-shell. So, the electrons will be filled in 3p sub-shell first. Hence, the ground state electronic configuration of neutral atom of phosphorous is,

$1s^22s^22p^63s^23p^3$

Answer 3 :

Element Rubidium Magnesium Aluminium

Symbol Rb Mg Al

Group number 1 2 13

Number of valence 1 2 3

electrons

The order of general reactivity on the basis of number of valence electrons.

Rb > Mg > Al

Reason : The reactivity is determined by the number of electrons present in the outermost shell that means the element which have 1 valence electron will be more reactive because they can easily lose electrons.

5 0

3 years ago