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Alchen [17]
3 years ago
5

Given the points J(-4,0) and K(0, 4), find the coordinates of the point P on directed

Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

We are given a ratio for this problem so we will use the formula for when we are given a ratio (as opposed to the formula for when you are given that the point you're looking for is a fraction of the way from one point to another, like 1/3 of the way from point A to point B. That's a different formula).

The formulas are for the x and y coordinates of the point in question:

x=\frac{bx_1+ax_2}{a+b}   and   y=\frac{by_1+ay_2}{a+b} where

a = 3 (from the ratio),

b = 1 (from the ratio),

x1 = -4, y1 = 0 (from point J)

x2 = 0, y2 = 4 (from point K). Filling in for x first:

x=\frac{1(-4)+3(0)}{3+1} gives us

x=\frac{-4}{4}=-1 and now for y:

y=\frac{1(0)+3(4)}{3+1} gives us

y=\frac{12}{4}=3

Therefore, the coordinates that partition that segment into the ratio of 3:1 are (-1, 3)

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