Find sin(90°). 45° A.0 В.1 C. square 2 D. square 2 / 2
1 answer:
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The horizontal distance traveled by the projectile is given as
where
V₀ = initial velocity, m/s
Note that
sin(2θ) = 2sinθ cosθ
Therefore, the horizontal distance traveled is
Because V₀ = 52 m/s, in order to travel a horizontal distance of 200 m, the correct equation to determine θ is
(52²/9.8) sin(2θ) = 200
or
275.92 sin(2θ) = 200
Answer: A
where
V₀ = initial velocity, m/s
Note that
sin(2θ) = 2sinθ cosθ
Therefore, the horizontal distance traveled is
Because V₀ = 52 m/s, in order to travel a horizontal distance of 200 m, the correct equation to determine θ is
(52²/9.8) sin(2θ) = 200
or
275.92 sin(2θ) = 200
Answer: A