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motikmotik
3 years ago
15

How many carbon atoms are in each mole of calcium carbonate?

Chemistry
1 answer:
xeze [42]3 years ago
6 0

Answer:

5 atoms are in each molecule of calcium carbonate

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Consumers get an idea of the building blocks of foods from ________________ and ________________.
oee [108]

Answer:

Ingredient lists and nutritional facts

Explanation:

The packaged food, a consumer purchases has all its details written on the food package which is also verified by a trusted government institution.

  • <u>Ingredient List </u>

The list tells each ingredient in food product by the food's common or usual name in the descending order by the weight.

  • <u>Nutrition Facts Label </u>

FDA requires this label on most of the packaged foods and the beverages. At top of Nutrition Facts label, there is written total number of the servings in container and serving size of food or drink. Serving size on label is based on amount of the food which people eat typically at one time. Rest of nutrition information on label is based usually on one serving of food or beverage.

7 0
3 years ago
Aqueous lead (II) nitrate, Pb(NO3)2 undergoes a double displacement reaction with aqueous sodium chloride, NaCl, in which a prec
Dvinal [7]

Answer:

{ \sf{Pb(NO_{3})_{2(aq)}  + 2NaCl _{(aq)} → 2NaNO_{3(aq)}  + PbCl _{2(s)} }} \\

8 0
3 years ago
PLEASE HELP ASAP!!!<br> K+ has how many electrons? <br> -19<br> -18<br> -20<br> -none of these
Y_Kistochka [10]

Answer:

Its 19.

Explanation:

K (potassium) has 19 electron according to the atomic number in the periodic table. The atomic number tells you the number of protons and electrons.

8 0
3 years ago
What energy do glow sticks convert to ?
MakcuM [25]
Is there any multiple choices?
8 0
3 years ago
Read 2 more answers
A 2.10g of unknown monoprotic acid is titrated with 38.10 mL of .265M NaOH. Calculate the molar mass of the ac? I already calcul
Shkiper50 [21]
V_{NaOH}=38,1mL=0,0381L\\&#10;C_{m}=0,265M\\\\&#10;n=C_{m}*V=0,265\frac{mol}{L}*0,0381L\approx0,0101mol

HR    +      NaOH ⇒ NaR + H₂O
1mol   :     1mol

0,0101mol \ \ \ \ \Rightarrow \ \ \  \ 2,1g\\&#10;1mol  \ \ \ \ \ \ \ \ \ \ \Rightarrow \ \ \ m\\\\&#10;m=\frac{1mol*2,1g}{0,0101mol}\approx 207,92g\\\\&#10;M_{HR}=207,92\frac{g}{mol}
5 0
3 years ago
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