let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
Answer:
firstly
we all know that the angles of a triangle they all add up to 180° meaning when you add them all they must give you 180°
88°+33°+L = 180° ( sum of angle in a ∆)
121° + L = 180°
L = 180° - 121°
L = 59°
Step-by-step explanation:
first you you must add all your angles and all equal to 180°
that you add the like terms
than you transpose 121° to the right hand side
C since that's the only triangle where A^2+B^2=C^2 (36+64=100).
