All categories

3 years ago

What is the Surface Area Formula for a Square Pyramid? I need the formula

Mathematics

1 answer:

Contact [7]3 years ago

8 0

Answer:

The surface area of a square pyramid is the sum of the areas of all its 4 triangular side faces with the base area of the square pyramid. If a, h, and l are the base length, the height of the pyramid, and slant height respectively, then the surface area of the square pyramid = a2+ 2al (or) a2+2a √a24+h2 a 2 4 + h 2 .

You might be interested in

Which value of m satisfies the inequality 170-7m >99?

Shkiper50 [21]

Answer:

$\huge \purple{m < \frac{71}{7} } \\$

Step-by-step explanation:

$170 - 7m > 99$

<u>Move 170 to the right side of the inequality</u>

$- 7m > 99 - 170 \\ - 7m > - 71$

<u>Divide both sides by - 7</u>

$\frac{ - 7m}{ - 7} > \frac{ - 71}{ - 7} \\ m > \frac{71}{7}$

Flip the signs

We have the final answer as

$m < \frac{71}{7} \\$

Hope this helps you

7 0

2 years ago

Read 2 more answers

Explain how you know that 7/12 is greater than 1/3 but less t than 2/3

Dmitrij [34]

You would make all the fractions have the same common denominator of 12. First you would keep the fraction 7/12 because the denominator is already 12. Next you would take the fraction 1/3 and multiply it by 4/4 and the new fraction for 1/3 becomes 4/12. Lastly you would take 2/3 and multiply that by 4/4 and the fraction becomes 8/12. Now you can compare the fractions with the same denominator. Therefore 7/12 is greater than 1/3 but less than 2/3

8 0

2 years ago

The value of the definite integral / 212x – sin(x) dx / 122x-sin(x) is

blondinia [14]

Hi there!

$\boxed{= 70 + cos(12) - cos(2) \approx 71.26}$

$\int\limits^{12}_{2} {x-sin(x)} \, dx$

We can evaluate using the power rule and trig rules:

$\int x^n = \frac{x^{n+1}}{n+1}$

$\int x = \frac{1}{2}x^{2}$

$\int -sin(x) = cos(x)$

Therefore:

$\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}$

Evaluate:

$(\frac{1}{2}(12^{2})+cos(12)) - (\frac{1}{2}(2^2)+cos(2))\\= (72 + cos(12)) - (2 + cos(2))\\\\= 70 + cos(12) - cos(2) \approx 71.26$

3 0

2 years ago

What is the answer need it

denis-greek [22]

Answer:

$\frac{7}{10} |$

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{2}{3}$ * $\frac{10}{10})$ + $(\frac{7}{10} * \frac{3}{3})$ = ?

Complete the multiplication and the equation becomes

$\frac{20}{30} + \frac{21}{30}$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{20+21}{30} = \frac{41}{30}$

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

$(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )$

The two fractions now have like denominators so you can add the numerators.

Then:

$\frac{41+-20}{30} = \frac{21}{30}$

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

$\frac{21/3}{30/3} =\frac{7}{10}$

Therefore:

$\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}$ |

8 0

2 years ago

Professor wonders whether a student's homework average (X) could be used to predict their final grade in the course (Y) . She ca

Anna11 [10]

Answer:

The dependent variable is the final grade in the course and is the vriable of interest on this case.

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

Step-by-step explanation:

On this case w ehave the following linear model:

$Y= 21.839 +0.724 X$

Where Y represent the final grade in the course and X the student's homework average. For this linear model the slope is given by $\beta_1 = 0.724$ and the intercept is $\beta_0 = 21.839$

Which is the dependent variable, and why?

The dependent variable is the final grade in the course and is the vriable of interest on this case.

Based on the material taught in this course, which of the following is the most appropriate alternative hypothesis to use for resolving this question?

Since we conduct a regression the hypothesis of interest are:

H0: $\beta_1 = 0$

H1: $\beta_1 \neq 0$

And if we reject the null hypothesis we can conclude that we have a significant relationship between the two variables analyzed.

3 0

2 years ago