When it switches to a lower orbital, the atom emits energy in the form of photons.
FeOH2 = 73.8602753 g/mol
FOLLOW ME FOR CLEARING YOUR NEXT DOUBT
M(NaOH)=15 g
v=600 ml=0.6 l
n(NaOH)=m(NaOH)/M(NaOH)
C=n(NaOH)/v=m(NaOH)/[M(NaOH)v]
C=15g/[40g/mol*0.6 l]=0.625 mol/l
0.625M
[H⁺]=7.5*10⁻²
pOH=14-pH=14+lg[H⁺]
pOH=14+lg(7.5*10⁻²)=14-1.125=12.875