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skelet666 [1.2K]
3 years ago
14

Greater than ___________ mcg/dl is considered a high level of morning cortisol.

Chemistry
1 answer:
Natalija [7]3 years ago
5 0

Greater than 23mcg/dl is considered a high level of morning cortisol.

Normally, cortisol levels rise during the early morning hours and are highest about 7AM. They drop very low in the evening and during the early phase of sleep. If you do not have this daily change (diurnal rhythm) in cortisol levels, you may have overactive adrenal glands. This condition is called Cushing's syndrome.

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Can someone answer this chemistry question​
Natalka [10]

Explanation:

this is because of the electrolysis and the hydrogen and oxygen the experiments and all that the conditions are all right you know that song

5 0
3 years ago
Consider the reaction N2(g) + 3H2(g) → 2NH3(g) Suppose that at a particular moment during the reaction, molecular hydrogen is re
rosijanka [135]

Answer:

The solution to the question is as follows

(a) The rate of ammonia formation = 0.061 M/s

(b) the rate of N₂ consumption = 0.0303 M/s

Explanation:

(a) To solve the question we note that the reaction consists of one mole of N₂ combining with three moles of H₂ to form 2 moles of NH₃

N₂(g) + 3H₂(g) → 2NH₃(g)

The rate of reaction of molecular hydrogen = 0.091 M/s, hence we have

3 moles of H₂ reacts to form 2 moles of NH₃, therefore

0.091 M of H₂ will react to form 2/3 × 0.091 M or 0.061 M of NH₃

Hence the rate of ammonia formation is 0.061 M/s

(b) From the reaction equation we have 3 moles of H₂ and one mole of N₂ being consumed at the same time hence

0.091 M of H₂ is consumed simultaneously with 1/3 × 0.091 M or 0.0303 M of N₂

Therefore the rate of consumption of N₂ = 0.0303 M/s

6 0
3 years ago
An atom has no electrical charge because _____.
Mars2501 [29]
Hey there! Great question;) Answer:it is neutrally charged because it has the same number of protons(positively charged iona) and electrons(negatively charged ions) I hope this helps:)
5 0
4 years ago
A buffer with a pH of 4.31 contains 0.31 M of sodium benzoate and 0.24 M of benzoic acid. What is the concentration of [ H 3 O ]
Mnenie [13.5K]

<u>Answer:</u> The hydronium ion concentration in the solution is 1.29\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles hydrochloric acid solution = 0.060 mol

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of HCl}=\frac{0.060}{1L}\\\\\text{Molarity of HCl}=0.060M

The chemical reaction for aniline and HCl follows the equation:

                   C_6H_5COO^-+HCl\rightarrow C_6H_5COOH+Cl^-

<u>Initial:</u>           0.24          0.060              0.31

<u>Final:</u>             0.18          -                     0.37

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{conjugate acid}]}{[\text{base}]})

pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of benzoic acid = 4.2

[C_6H_5COO^-]=0.18M

[C_6H_5COOH]=0.37M

pH = ?

Putting values in equation 1, we get:

pH=4.2+\log(\frac{0.18}{0.37})\\\\pH=3.89

To calculate the hydronium ion concentration in the solution, we use the equation:

pH=-\log[H_3O^+]

pH = 3.89

Putting values in above equation, we get:

3.89=-\log[H_3O^+]

[H_3O^+]=10^{-3.89}=1.29\times 10^{-4}M

Hence, the hydronium ion concentration in the solution is 1.29\times 10^{-4}M

3 0
3 years ago
Dr. von Waldner conducts research on depression. His hypothesis is that depression results from maladaptive thought patterns. Fr
Nimfa-mama [501]
The answer is C- cognitive
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