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skelet666 [1.2K]
3 years ago
14

Greater than ___________ mcg/dl is considered a high level of morning cortisol.

Chemistry
1 answer:
Natalija [7]3 years ago
5 0

Greater than 23mcg/dl is considered a high level of morning cortisol.

Normally, cortisol levels rise during the early morning hours and are highest about 7AM. They drop very low in the evening and during the early phase of sleep. If you do not have this daily change (diurnal rhythm) in cortisol levels, you may have overactive adrenal glands. This condition is called Cushing's syndrome.

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Suppose a piece of silver jewelry contains 5.23×1022 atoms of silver (ag). part a how many dozens of silver atoms are in the pie
IgorC [24]
Answer:
number of dozens = 4.35834 * 10^21 dozens

Explanation:
A dozen contains 12 atoms. To know the number of dozens containing
5.23 * 10^22 atoms, all we have to do is cross multiplication as follows:
1 dozen ...........> 12 atoms
?? dozens ......> <span>5.23 * 10^22 
number of dozens = (</span><span>5.23 * 10^22 *1) / (12)
number of dozens = 4.35834 * 10^21 dozens

Hope this helps :)</span>
7 0
3 years ago
Which is the frequency of the wave shown?
ratelena [41]

Answer:

The frequency of wave is 0.125 Hz.

Explanation:

Frequency:

"It is an event repeat itself in a given period of time"

The unit of frequency is the Hz . If time is measured in seconds then frequency will be in Hz. Hz is equal to the per second.

Formula:

f = 1/ T

f = 1/ 8 sec

f = 0.125 Hz

5 0
3 years ago
In some areas of the Earth, the crust is squeezed and pushed upward. This is a _______ process in that it directly forms _______
NemiM [27]
So..... I believe this is a Convergent boundary and mountains..
7 0
3 years ago
Read 2 more answers
The orbital period of planet Venus is 0.62 years. What is its distance from the sun?
Vikki [24]

Kepler's third law shows the relationship between the orbital period of an object and the distance between the object and the object it orbits.

The simplified version of this law is: P^2 = a^3

Where,

P = period of the orbit in years = 0.62 years

a = average distance from the object to the object it orbits in AU. The astronomical unit AU is a unit of length which is roughly equivalent to the distance from Earth to the Sun.

Therefore calculating for a:

0.62 ^ 2 = a ^ 3

a = 0.62 ^ (2/3)

a = 0.727 AU = 0.72 AU

Therefore we can interpret this as: The distance from Venus to the Sun is about 72% of the distance from Earth to Sun.

<span>Answer: B. 0.72 AU</span>

5 0
3 years ago
Help me I hate science so much​
mestny [16]

Answer:

it would be sciemce

Explanation:

yeah because its  hargf

8 0
3 years ago
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