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skelet666 [1.2K]
3 years ago
14

Greater than ___________ mcg/dl is considered a high level of morning cortisol.

Chemistry
1 answer:
Natalija [7]3 years ago
5 0

Greater than 23mcg/dl is considered a high level of morning cortisol.

Normally, cortisol levels rise during the early morning hours and are highest about 7AM. They drop very low in the evening and during the early phase of sleep. If you do not have this daily change (diurnal rhythm) in cortisol levels, you may have overactive adrenal glands. This condition is called Cushing's syndrome.

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Explanation:

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4 0
3 years ago
Read 2 more answers
Question 4 (1 point)
bagirrra123 [75]

Answer:

Argon

Explanation:

The element that would most likely be a good substitute for neon is "argon".

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Argon, as an inert gas is often used whenever an inert atmosphere is needed. Argon is used in incandescent light bulbs. It is used to stop oxygen from corroding the filament. It is also used by welders to protect weld area.

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5 0
3 years ago
Balance the following redox equation and identify the element oxidized, the element reduced, the oxidizing agent, and the reduci
butalik [34]
Cr2O72- + 6CH3OH + 8H+ --- > 6CH2O + 2Cr3+ + 7H2O
3 0
3 years ago
Suppose 3.68g of zinc was allowed to react with hydrochloric acid to produce zinc chloride and hydrogen gas. How much zinc chlor
valentina_108 [34]

Answer:

Percent yield = 86.2%

Explanation:

Given data:

Mass of zinc = 3.68 g

Mass of zinc chloride = ?

Percent yield = ?

Actual yield = 7.12 g

Solution:

Chemical equation:

Zn + 2HCl  → ZnCl₂  + H₂

Number of moles of zinc:

Number of moles  = Mass /molar mass

Number of moles = 3.68 g / 65.38 g/mol

Number of moles  = 0.06 mol

Now we will compare the moles of ZnCl₂ with zinc.

                 Zn            :               ZnCl₂

                  1               :               1

                 0.06           :            0.06

Theoretical yield of zinc chloride:        

Mass of ZnCl₂ = moles × molar mass

Mass of ZnCl₂ = 0.06 mol × 136.286 g/mol

Mass of ZnCl₂ =  8.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 7.12 g/ 8.2 g × 100

Percent yield = 86.2%

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How many grams of CO2 are in 1.5L of a 1.2 M solution?
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