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3 years ago

Plz I need help is the 2nd time I post this

Chemistry

1 answer:

pychu [463]3 years ago

8 0

Answer:

2--->C

6---->E

3---->D

4--->A

5--->B

1---->F

Explanation:

I think so, sorry if its wrong.

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2C2H6 + 8O2 = 4CO2 + 6H2O

Neporo4naja [7]

Answer:

4 moles of carbon

6 moles of water

Explanation:

I think as there no data given u have to is the numbers infront of the equation e.g 4CO2 so 4.

hope this helps :)

4 0

3 years ago

Which description identifies the correct charge of each atomic particle? A. electron = positive; proton = negative; neutron = no

stiv31 [10]

B. electron = negative; proton = positive; neutron = no charge

3 0

3 years ago

In an acid-base titration, a student uses 21.35 mL of 0.150 M NaOH to neutralize 25.00 mL of H2SO4. How many moles of acid are i

GalinKa [24]

Answer: There are 0.006 moles of acid in the flask.

Explanation:

Given: $V_{1}$ = 21.35 mL, $M_{1}$ = 0.150 M

$V_{2}$ = 25.0 mL, $M_{2}$ = ?

Formula used to calculate molarity of $H_{2}SO_{4}$ is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M$

As molarity is the number of moles of a substance present in a liter of solution.

Total volume of solution = $V_{1} + V_{2}$

= 21.35 mL + 25.0 mL

= 46.36 mL (1 mL = 0.001 L)

= 0.04636 L

Therefore, moles of acid required are calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol$

Thus, we can conclude that there are 0.006 moles of acid in the flask.

3 0

3 years ago

In the reaction

ivolga24 [154]

Water is the BL base if it accepted a proton from NH4.
Can I get brainliest please?

7 0

2 years ago

Which equation represents the correct net ionic equation for the reaction between Ca(OH)2 and H2SO4?

Georgia [21]

Answer: The correct net ionic equation for the reaction is $2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)$

Explanation:

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation is:

$Ca(OH)_2(aq)+H_2SO_4(aq)\rightarrow CaSO_4(aq)+2H_2O(l)$

The complete ionic equation follows:

$Ca^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)$

As calcium and sulfate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

$2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)$

Hence, the correct net ionic equation for the reaction is $2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)$

7 0

3 years ago