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aliina [53]
2 years ago
13

Plz I need help is the 2nd time I post this

Chemistry
1 answer:
pychu [463]2 years ago
8 0

Answer:

2--->C

6---->E

3---->D

4--->A

5--->B

1---->F

Explanation:

I think so, sorry if its wrong.

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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
KIM [24]

Answer:

ΔH = -470.4kJ

Explanation:

It is possible to sum 2 or more reactions to obtain the ΔH of the reaction you want to study (Hess's law). Using the reactions:

1. CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s)ΔH = −414kJ

2. 6C2H2(g) + 3CO2(g) + 4H2O(g) → 5CH2CHCO2H(g)ΔH = 132kJ

6 times the reaction 1.

6CaC2(s) + 12H2O(l) → 6C2H2(g) + 6Ca(OH)2(s)ΔH = −414kJ*6 = -2484kJ

This reaction + 2:

6CaC2(s) + 3CO2(g) + 16H2O(l) →  + 6Ca(OH)2(s) + 5CH2CHCO2H(g) ΔH = -2484kJ + 132kJ = -2352kJ

As we want to calculate the net change enthalpy in the formation of just 1 mole of acrylic acid we need to divide this last reaction in 5:

6/5CaC2(s) + 3/5CO2(g) + 16/5H2O(l) →  + 6/5Ca(OH)2(s) + CH2CHCO2H(g) ΔH = -2352kJ / 5

<h3>ΔH = -470.4kJ</h3>

4 0
2 years ago
can someone help and lmk if my answers are correct i don’t think they are please help i’ll give brainliest thank you
Dafna11 [192]

Answer:

5=C, every action has an equal or opposite reaction,

6=B, since it has less air drag and more force exerted on it

7= You're correct

5 0
3 years ago
CalcuLate the velocity of an electron ejected if 300.0 mm of light is applied to the surface. A wavelength of 795 nm has suffici
worty [1.4K]
The equation relating velocity and wavelength is written below:

v = λf
where λ is the wavelength in m while f is frequency in 1/s.

Let's determine first the frequency from the speed of light:
c = distance/time, where c is the speed of light equal to 3×10⁸ m/s
3×10⁸ m/s = (300 mm)(1 m/1000 mm)/ time
time = 1×10⁻⁹ seconds
Since f = 1/t,
f = 1/1×10⁻⁹ seconds = 10⁹ s⁻¹

Thus,
v = (795×10⁻⁹ m)(10⁹ s⁻¹)
v = 795 m/s
8 0
2 years ago
Read the scenario.
irakobra [83]
2H2+O2→2H2O
We have to be aware that the number of atoms are the same on both reactant side and product side.
5 0
3 years ago
Read 2 more answers
What if benzene sulphonyl chloride react with tertiary amine???? Name this reagent???​
aniked [119]

Explanation:

<h3>Hinsberg reagent is an alternative name for benzene sulfonyl chloride. This name is given for its use in the Hinsberg test for the detection and distinction of primary, secondary, and tertiary amines in a given sample. This reagent is an organosulfur compound.</h3>
6 0
2 years ago
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