During the collision between two balls on the pool table there is no external force along the line of collision between them
Since there is no external force on it so here we can say
here we have
so we can say
since there is no external force so we can say during the collision the momentum of two balls will remain conserved
The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration <em>a</em> is such that
4 m/s = <em>a</em> (2.5 s) → <em>a</em> = (4 m/s) / (2.5 s) = 1.6 m/s²
Then the force applied to the box has a magnitude <em>F</em> such that
<em>F</em> = (10 kg) (1.6 m/s²) = 16 N
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
