All categories

3 years ago

Kyle has the mass of 54 kg and is jogging at a velocity of m/s. What is Kyle’s kinetic energy

Physics

2 answers:

lubasha [3.4K]3 years ago

6 0

you would have to do 1/2mv^2 so you should get 243J

inysia [295]3 years ago

3 0

m = mass = 54 kg

v = velocity = 3 m/s

KE = (1/2)*m*v^2

KE = (1/2) * 54 * (3)^2

KE = 243 J

Hope this helps!

You might be interested in

Which weather event is capable of destroying homes and uprooting trees due to a low pressure area at its center

Bond [772]

You're talking about a <em>tornado</em>.

It's not so much the low pressure that's so dangerous in the center of a tornado. It's more a matter of the high winds that are <em>caused </em>by the low pressure.

7 0

4 years ago

Read 2 more answers

Find the speed of a long distance runner who runs 30km in 6 hours

slava [35]

30mi/6hrs is a speed of 5 mph, which converts to a pace of 12 min/mi.

7 0

3 years ago

Read 2 more answers

Question 3 of 10

Eva8 [605]

Answer:

D. Newton's second law

Explanation:

Newton's second law of motion states that force of an object is a product of its mass and its acceleration.

Mathematically, F= ma where m is mass and a is acceleration

So from the statement above : The acceleration of an object is proportional to the force applied to it and inversely proportional to its mass , it can be seen from the formula variation as;

F= ma -----making a the subject of the formula

a= F/ m

a= 1/m * F --------- a is inversely related to m as you can see from 1/m but directly related to F hence;

Increase in mass with the same force applied causes the body to accelerate slower where as when force increases, the body accelerates faster.

5 0

3 years ago

(a) Calculate the force (in N) needed to bring a 1100 kg car to rest from a speed of 85.0 km/h in a distance of 125 m (a fairly

nasty-shy [4]

(a) -2451 N

We can start by calculating the acceleration of the car. We have:

$u=85.0 km/h = 23.6 m/s$ is the initial velocity

v = 0 is the final velocity of the car

d = 125 m is the stopping distance

So we can use the following equation

$v^2 - u^2 = 2ad$

To find the acceleration of the car, a:

$a=\frac{v^2-u^2}{2d}=\frac{0-(23.6 m/s)^2}{2(125 m)}=-2.23 m/s^2$

Now we can use Newton's second Law:

F = ma

where m = 1100 kg to find the force exerted on the car in order to stop it; we find:

$F=(1100 kg)(-2.23 m/s^2)=-2451 N$

and the negative sign means the force is in the opposite direction to the motion of the car.

(b) $-1.53\cdot 10^5 N$

We can use again the equation

$v^2 - u^2 = 2ad$

To find the acceleration of the car. This time we have

$u=85.0 km/h = 23.6 m/s$ is the initial velocity

v = 0 is the final velocity of the car

d = 2.0 m is the stopping distance

Substituting and solving for a,

$a=\frac{v^2-u^2}{2d}=\frac{0-(23.6 m/s)^2}{2(2 m)}=-139.2 m/s^2$

So now we can find the force exerted on the car by using again Newton's second law:

$F=ma=(1100 kg)(-139.2 m/s^2)=-1.53\cdot 10^5 N$

As we can see, the force is much stronger than the force exerted in part a).

8 0

3 years ago

__________ is a developmental defect in which a portion of the spinal cord protrudes outside the vertebrae.

7nadin3 [17]

Answer: Spina bifida

Explanation:

Spina bifida is a developmental defect in which a portion of the spinal cord protrudes outside the vertebrae.

Spina bifida is a birth defect that occurs when there is improper formation of the spine and spinal cord. It's a type of neural tube defect. The structure in a developing embryo that eventually becomes the baby's brain, spinal cord and the tissues that enclose them is the neutral tube.

3 0

3 years ago