NH4OH is the answer. Hope this helps you.
Answer: WAIT WHATTTT i have that same test due today and the answer is in explanation
Explanation:
Bike, truck train. we are in the same school i think. Its imma say the incisal JMES Im Lusi i used to help in the library
Answer:
![x=(0.088m)\cos(\sqrt{\frac{k}{m} } t)](https://tex.z-dn.net/?f=x%3D%280.088m%29%5Ccos%28%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20%20t%29)
Explanation:
We first identify the elements of this simple harmonic motion:
The amplitude A is 8.8cm, because it's the maximum distance the mass can go away from the equilibrium point. In meters, it is equivalent to 0.088m.
The angular frequency ω can be calculated with the formula:
![\omega =\sqrt{\frac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%20%3D%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%7D)
Where k is the spring constant and m is the mass of the particle.
Now, since the spring starts stretched at its maximum, the appropriate function to use is the positive cosine in the equation of simple harmonic motion:
![x=A\cos(\omega t)](https://tex.z-dn.net/?f=x%3DA%5Ccos%28%5Comega%20t%29)
Finally, the equation of the motion of the system is:
or
![x=(0.088m)\cos(\sqrt{\frac{k}{m} } t)](https://tex.z-dn.net/?f=x%3D%280.088m%29%5Ccos%28%5Csqrt%7B%5Cfrac%7Bk%7D%7Bm%7D%20%7D%20%20t%29)