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Mariulka [41]
3 years ago
11

What value is closest to the mass of the atom?....

Physics
2 answers:
Sveta_85 [38]3 years ago
6 0
The answer would be 6amu
stira [4]3 years ago
5 0

ANSWER:

THE ANSWER IS c. 10 AMU

~batmans wife dun dun dun...aka ~serenitybella

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Active listening includes all of the following EXCEPT: A. paraphrasing B. clarifying C. ignoring D. empathizing Please select th
scoray [572]

Answer:

C: Ignoring

Explanation:

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8 0
3 years ago
If a ball is launched horizontally at 40 m/s
vaieri [72.5K]

Answer:

40m/s

Explanation:

The horizontal component of velocity remains constant because there are no external forces in that direction

By applying motion equations, V= U+ at

where ,

  • v - final velocity
  • u - initial velocity
  • a-acceleration
  • t - time

v = u +at

As no force act on the ball ( we neglect air resistance here) no acceleration is seen,

So v = u = 40m/s

4 0
3 years ago
How much time will it take to perform 440 joule of work at a rare of 11 w?​
kifflom [539]

Answer:

40sec

Explanation:

Data

Work = 440 J

Power= 11watt

time = ?

Power = work done/time

===> time = work done/power

= 440/11

= 40sec

7 0
2 years ago
Name three elements that are good conductors of heat
Vera_Pavlovna [14]
Copper, gold and silver are three of them.
7 0
3 years ago
a container of water is knocked off a 10.0 meter high ledge with a horizontal velocity of 1.00 meters/second. calculate the time
Evgen [1.6K]

Answer:

1.43 s

Explanation:

The time it takes for the container to reach the ground is determined only by the vertical motion of the container, which is a free-fall motion, so a uniformly accelerated motion with a constant acceleration of g=9.8 m/s^2 towards the ground.

The vertical distance covered by an object in free fall is given by

S=ut + \frac{1}{2}at^2

where

u = 0 is the initial vertical speed

t is the time

a= g = 9.8 m/s^2 is the acceleration

since u=0, it can be rewritten as

S=\frac{1}{2}gt^2

And substituting S=10.0 m, we can solve for t, to find the duration of the fall:

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(10.0 m)}{9.8 m/s^2}}=1.43 s

3 0
3 years ago
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