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victus00 [196]
3 years ago
6

The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.00

59 m/s/s, what is the sun’s acceleration toward the Earth?
Physics
1 answer:
saul85 [17]3 years ago
5 0

Answer:

this is the answer according to my calculations

Explanation:

0.001.9

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If you wanted to increase the gravitational force between two objects what would you do
adelina 88 [10]
Double the force on the object
6 0
4 years ago
Read 2 more answers
a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh
Viefleur [7K]
Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing.  Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

             F = (mass) · (speed)² / (radius).

For this particular car, the force is

                    (2,000 kg) · (25 m/s)² / (80 m)

                 = (2,000 kg) · (625 m²/s²) / (80 m)

                 = (2,000 · 625 / 80)  (kg · m / s²)

                 =              15,625  newtons .
5 0
4 years ago
Which process is not required for an animal to obtain energy from food?
Romashka [77]

Complete Question:

Which process is not required for an animal to obtain energy from food?

a. Secretion.

b. Digestion.

c. Excretion.

d. Ingestion.

Answer:

c. Excretion.

Explanation:

Excretion is a metabolic process in which living organisms gets their system rid of metabolic waste, water and excess ions. This is usually done with the aid of kidney, skin and lungs in all vertebrates.

Example of excretions are urination, sweating and defecation.

5 0
4 years ago
In a particular run of the “Archimedes principle” experiment a particular unknown substance is found to have a “dry mass” of 4.5
iris [78.8K]

Answer:

D = 18000 kg/m3

V = 2.5*10{-7}m3

Explanation:

From the Archimedes principle,

Weight of fluid displaced = W_{air} - W_{water}

W_{air} = 4.5 gm

W_{water} = 4.25 gm

W = [4.5 - 4.25]*9.81*10^{-3}

W = 2.4525*10{-3} N

\frac{density\ of\ object}{density\ of\ fluid} = \frac{weight\ in\ air}{weight\ of\ displaced\ fluid}

Density\ of\ object = \frac{D_{water}*Weight\ in\ air}{weight\ of\ displaced\ water}

D = \frac{1000*4.5*10^{-3}*9.8}{2.4525*10^{-3}}N

D = 18000 kg/m3

b) object Volume can be obtained  as ,

V = \frac{m}{D} = \frac{4.5*10^{-3}}{18000}

V = 2.5*10{-7}m3

7 0
3 years ago
Why are common measurement systems important
kenny6666 [7]
So that international people don't mistake units for others. ex 1 inch could be mistaken for 1 cm in non American countries
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