Answer:
Explanation:
This is a simple F = ma equation. We have the mass and we have the acceleration, so
F = 1298(17) and
F = 22066 which rounds correctly to
F = 22000N
Answer:
(a) W=217 J
(b) Tc=378K
(c) e=0.39=39%
Explanation:
For part (a)
We to calculate the mechanical work W the engine does. By knowing QC and QH can obtain the work using equation
W = IQHI — IQcl .....................eq(1)
Put given values for QH and QC into equation (1) to get
the mechanical work of the engine
W = 550 - 335
W=217 J
For part (b)
We want to determine the temperature of low temperature reservoir which means Tc
IQc|/|Qh| =TC/TH
for Tc
Tc=(IQc|/|Qh|)*TH
Now we can put values
Tc= 620K (335/
550.1)
Tc=378K
For part (c)
Here we want to find the thermal efficiency (e) of the cycle
e=1-TC/TH
e=1-(378/620)
e=0.39=39%
Answer:
(a) α = 35.20 rad/s^2
(b) θ = 802°
(c) v = 139.73 cm/s
(d) a = 156.64 cm/s^2
Explanation:
(a) To find the angular acceleration of the disc you use the following formula:
(1)
w: angular speed of the disc = 31.4 rad/s
wo: initial angular speed = 0 rad/s
t: time = 0.892s
You replace the values of the parameters in the equation (1):
The angular acceleration of the disc, for the given time, is 35.20rad/s^2
(b) To calculate the angle describe by the disc in such a time you use:
(2)
In degrees you have:
The angle described by the disc is 802°
(c) To calculate the tangential speed of the microbe for t=0.892s, you use the following formula:
(3)
w: angular speed for t = 0.892s = 31.4rad/s
r: radius of the disc = 4.45cm
The tangential speed is 139.73 cm/s
(d) The tangential acceleration is calculated by using the following formula:
α: angular acceleration for t=0.892s
The tangential acceleration is 156.64cm/s^2
V = f * wavelength
as we know electromagnetic wave has speed equal to light, so
3 * 10^8 = f * 1.3
f = 2.3 * 10^8 hertz
f = 230 mega hertz