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irga5000 [103]
3 years ago
9

Hi im being timed please help im trying to raise my F in the class before graduation

Physics
1 answer:
kogti [31]3 years ago
3 0

Answer:

c?? i think because of the graphs

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Science, pls!!
dem82 [27]

Answer:

I would say that the answer is B because it is the most reasonable one

Explanation:

5 0
3 years ago
Read 2 more answers
How much heat is needed to condense 22.25 grams of nitrogen gas at –195.8°C? The latent heat of vaporization of nitrogen is 199.
morpeh [17]

The correct answer to the question is : 4427.75 J.

EXPLANATION :

As per the question, the mass of the nitrogen gas m = 22.25 gram.

The latent heat of vaporization of nitrogen L_{v} =199.0\ J/g

As per the question, the nitrogen gas will condense. During condensation, the nitrogen gas will lose or release heat equal to its latent heat.

Hence, the heat released by nitrogen gas Q = mL_{v}

                                                                          = 22.25 × 199.0 J

                                                                          = 4427.75 J.

Hence, the amount of heat released will be 4427.75 J.

5 0
3 years ago
Read 2 more answers
How long does it take to raise the temperature of the air in a good-sized living room (3.00m×5.00m×8.00m) by 10.0∘C? Note that t
QveST [7]

Answer : The time required is, 16.1 minutes.

Explanation :

First we have to calculate the amount of heat required to increase the temperature is:

Q=mC\Delta T\\\\Q=\rho VC\Delta T

(m=\rho V)

where,

Q = amount of heat required = ?

m = mass

\rho = density of air = 1.20kg/m^3

V = volume of air

C = specific heat of air = 1006J/kg^oC

\Delta T = change in temperature = 10.0^oC

Now put all the given values in above formula, we get:

Q=\rho VC\Delta T

Q=(1.20kg/m^3)\times (3.00m\times 5.00m\times 8.00m)\times (1006J/kg^oC)\times (10.0^oC)

Q=1.449\times 10^6J

Now we have to calculate the time required.

Formula used :

t=\frac{Q}{P}

where,

t = time required = ?

Q = amount of heat required = 1.449\times 10^6J

P = power = 1500 W

Now put all the given values in above formula, we get:

t=\frac{1.449\times 10^6J}{1500W}

t=966s\times \frac{1min}{60s}=16.1min

Thus, the time required is, 16.1 minutes.

3 0
3 years ago
Use these values: distance traveled is 30.0 km; time elapsed is 40.0 minutes; average power output is 370 watts. Determine the t
serious [3.7K]

Explanation:

It is known that the relation between power and work is as follows.

           Power = \frac{\text{work done}}{Time}

As it is given that power is 370 watts and time is 40 minutes. First, we will convert minutes into seconds as follows.

               40 min \times \frac{60 sec}{1 min}

                 = 2400 sec

Now, total power or energy is calculated as follows.

              Power = \frac{\text{work done}}{Time}

                         = \frac{370 watts}{2400 sec}        

                         = 888000 J

As 1 kJ = 1000 J. So, convert 888000 J into kJ as follows.

                 \frac{888000}{1000} kJ

                  = 888 kJ

therefore, we can conclude that total energy expended by the cyclist is 888 kJ.

4 0
3 years ago
Albert Einstein was a famous physicist.
Eva8 [605]
Genus’s mastermind hope that helps
4 0
3 years ago
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