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Sergeeva-Olga [200]
3 years ago
7

Determine the magnitude of the electric field at the point P. Express your answer in terms of Q, x, a, and k. Express your answe

r in terms of the variables Q, x, a, k, and appropriate constants.
Physics
1 answer:
Sav [38]3 years ago
8 0

Complete Question

The question image is in the first uploaded image

Answer:

E=\frac{KQ*4xa}{(x^2-a^2)^2}

Explanation:

From the question we are told that

Distance b/w Q mid point and P is given as x

Generally the equation for magnitude of the electric field at the point P is given as

E=\frac{kQ}{d^2}

where

k=\frac{1}{4\pi e_0}

d=x^2-a^2

Therefore

E= \frac{1}{4\pi e_0} \frac{Q}{(x^2-a^2)^2}- \frac{1}{4\pi e_0} \frac{Q}{(x^2+a^2)^2}

E= \frac{Q}{4\pi e_0} (\frac{1}{(x^2-a^2)^2}-  \frac{1}{(x^2+a^2)^2})

Therefore equation for magnitude of the electric field at the point P is

E=\frac{KQ*4xa}{(x^2-a^2)^2}

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<em>The first blank is </em><em>robust watermark</em>; a robust watermark will not resist tampering.

<em>The second blank is </em><em>fragile watermark</em><em>;</em> a fragile watermark will resist manipulations of the media.

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A watermark is a faint design made in paper during manufacture that is visible when held against the light and clearly identifies the maker.

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7 0
2 years ago
How much heat do you need to raise the temperature of 150 g of oxygen from -30c to -15c?
Naddika [18.5K]
The amount of heat needed to raise the temperature of a substance by \Delta T is given by
Q=m C_s \Delta T
where
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Cs is its specific heat capacity
\Delta T is the increase in temperature

For oxygen, the specific heat capacity is approximately 
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The variation of temperature for the sample in our problem is 
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while the mass is m=150 g, so the amount of heat needed is
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4 0
3 years ago
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When she rides her bike, she gets to her first classroom building 36 minutes faster than when she walks. Of her average walking
postnew [5]

Answer:

d=2.4\ miles

Explanation:

Given:

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  • average biking speed, v_b=12\ mph

<u>According to given condition:</u>

t_w=t_b+\frac{36}{60}

where:

t_w= time taken to reach the building by walking

t_b= time taken to reach the building by biking

We know that,

\rm time=\frac{distance}{speed}

so,

\frac{d}{v_w} =\frac{d}{v_b} +\frac{36}{60}

\frac{d}{3}=\frac{d}{12} +\frac{3}{5}

d=2.4\ miles

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An object of mass 0.5 kg is swung in uniform circular motion. The radius is 2 meters, and the force exerted is 4 N. Calculate th
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Using
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Risk of return on investment is higher than other forms of energy generation.
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