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riadik2000 [5.3K]
3 years ago
9

A big league hitter attacks a fastball! The ball has a mass of 0.16 kg. It is pitched at 38 m/s. After the player hits the ball,

it is now traveling 44 m/s in the opposite direction. The impact lasted 0.002 seconds. How big of a force did the ballplayer put on that ball?
Physics
1 answer:
Levart [38]3 years ago
7 0
Force = rate of change of momentum = 0.16(38 + 44)/0.002 = 6560 N
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