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Igoryamba
2 years ago
8

A mass of (200 of hot water at (75, 0 degrees * C) is mixed with cold water of mass M at (5, 0 degrees * C) The final temperatur

e of the mixture is (25, 0 degrees * C) What is the mass of the cold water (M)
Physics
2 answers:
RUDIKE [14]2 years ago
6 0

∆T for hot water

  • 75-25
  • 50°C

∆T for cold water

  • 25-5
  • 20°C

Both are equal according law of conservation of energy

\\ \rm\Rrightarrow m_1c\delta T_0=m_2c\delta

\\ \rm\Rrightarrow 200(50)=m_2(20)

\\ \rm\Rrightarrow 10000=m_2(20)

\\ \rm\Rrightarrow m_2=500g=0.5kg

Ratling [72]2 years ago
3 0

Q in = Q out

mcΔt in = mcΔt out (c = equal)

mΔt in = mΔt out

200 x  (75-25) = M x (25-5)

M = 500 g

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Sonja [21]

Answer:

Intensity, I=1.101\ W/m^2

Explanation:

Power of the light bulb, P  = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

I=\dfrac{P}{A}

I=\dfrac{P}{4\pi r^2}

I=\dfrac{40\ W}{4\pi (1.7\ m)^2}

I=1.101\ W/m^2

So, the intensity of light is 1.101\ W/m^2.

6 0
3 years ago
A ball is thrown horizontally from the top of a 60.0-m building and lands 100.0 m from the base of thebuilding. Ignore air resis
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Answer:

a)3.5s

b)28.57m/S

c)34.33m/S

d)44.66m/S

Explanation:

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we will solve this exercise numeral by numeral

a) to find the time the ball takes in the air we must consider that vertically the ball experiences a movement with constant acceleration whose value is gravity (9.81m / S ^ 2), that the initial vertical velocity is zero, we use the following equation for a body that moves with constant acceleration

Y= VoT+0.5gt^{2}

where

Vo = Initial speed =0

T = time

g=gravity=9.81m/s^2

y = height=60m

solving for time

Y=0.5gt^2\\t=\sqrt{\frac{Y}{0.5g} } \\t=\frac{60}{0.5(9.81)} \\

T=3.5s

b)The horizontal speed remains constant since there is no horizontal acceleration. with the value of the distance traveled (100m) and the time that lasts in the air (3.5s) we estimate the horizontal speed

V=\frac{x}{t} =\frac{100}{3.5}=28.57m/s

c)

to find the final vertical velocity we use the equations for motion with constant velocity as follows

Vf=Vo+g.t    

Vf=0+(9.81 )(3.5)=34.335m/S          

d)Finally, to find the resulting velocity, we add the horizontal and vertical velocities vectorially, this is achieved by finding the square root of the sum of its squares

V=\sqrt{Vx^2+Vy^2} =\sqrt{34.33^2+28.57^2} =44.67m/S

7 0
3 years ago
| A T-ball with a mass of 0.6 kg travels in the
r-ruslan [8.4K]

Answer:

|I|=6\ Kg.m/s

F=120\ N

Explanation:

Impulse and Momentum

They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

p_o=m.v_o

When a force is applied, the speed changes to v_1 and the new momentum is

p_1=m.v_1

The change of momentum is

\Delta p=p_1-p_0=m(v_1-v_o)

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

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Part 1

The T-ball initially travels at 10 m/s and then suddenly it's stopped by the glove. The final speed is zero, so

\Delta p=0.6\ Kg(0-10\ m/s)=-6\ Kg.m/s

The impulse is

I=\Delta p

I=-6\ Kg.m/s

The magnitude is

|I|=6\ Kg.m/s

Part 2

The force can be computed from the formula

I=F.t

The direction of the impulse the T-ball receives is opposite to the direction of the force exerted by the ball on the glove, thus I_b=6\ kg.m/s

\displaystyle F=\frac{I}{t}=\frac{6\ kg.m/s}{0.05\ s}

\boxed{F=120\ N}

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Answer:

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Explanation:

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