When v= 4.8 m/s:
E.K=mv²/2
=3,1(4.8)²/2
=35.712J
when v= 2(4.8):
E.K=mv²/2
=3.1(9.6)²/2
=142.848J
Answer:
a) 13.59 m/s²
b) 67.95 m/s
c) 169.875 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
m = Mass
Force

Acceleration of the jet is 13.59 m/s²

Velocity attained at 5 seconds is 67.95 m/s

Distance traveled in the 5 seconds is 169.875 m
Use this equation (v=Δx/t); plug in velocity (0.500 m/s) and the time (2.4 s), then solve for displacement… (Δx=1.2 m)