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3 years ago

10

Can yall give me the steps in how you do it if yall do it for me i will give yall more points

2 answers:

marysya [2.9K]3 years ago

3 0

Answer:

Step-by-step explanation:

Easy way to do it is to look at the constant, the number that does not have a variable, and that will be your y-intercept, so that is your first point. Then, you take your slope and do rise over run. For example, if the slope is 1/4, then you would rise up one, and run right 4. If the slope was -1/2, then you would rise up one, and run left 2, or rise down one and run right 2. This will give you your second and third points and you can easily graph your line from there.

timurjin [86]3 years ago

3 0

Answer:

Here is some steps

Step-by-step explanation:

Easy way to do it is to look at the constant, the number that does not have a variable, and that will be your y-intercept, so that is your first point. Then, you take your slope and do rise over run. For example, if the slope is 1/4, then you would rise up one, and run right 4. If the slope was -1/2, then you would rise up one, and run left 2, or rise down one and run right 2. This will give you your second and third points and you can easily graph your line from there.

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ILL MARK BRAINLIEST!!! PLS HELP!!! A car purchased for $18,000 depreciates annually at a rate of 5%.

Vlad [161]

Answer:

Step-by-step exlanation:

What you do is $18,000 x 5% which is 900 and then you do 900 x 10 = 9000!

5 0

3 years ago

Need help on the blanks. Pretty lost atm

nlexa [21]

Answer:

-108.26
-108.13
-108.052
-108.026
-108

Step-by-step explanation:

A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.

The average velocity on the interval [a,b] will be ...

v avg = (y(b) - y(a))/(b-a)

Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...

v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t

This can be computed for each of the t-values given. The results are shown in the attached table.

__

We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.

The estimated instantaneous velocity is -108 ft/s.

_____

We can simplify the average velocity equation to ...

v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t

= (48t -26(t^2 +6t))/t

= 48 -26t -156

<em> v avg = -108 -26t</em>

Then the average velocity at t=0 is -108.

5 0

3 years ago

Solve for y:<br> 9x + 4y = -12<br> Please help!!!

Lyrx [107]

Answer:

<h2> y = -⁹/₄x - 3</h2>

Step-by-step explanation:

9x + 4y = -12 {subtract 9x from both sides}

4y = -9x - 12 {divide both sides by 4}

y = -⁹/₄x - 3

5 0

3 years ago

Write anwsers as fractions using / as fraction bar and write the greater value first

puteri [66]

Answer:

Final answer is $\frac{3}{2}$ or $\frac{1}{2}$ .

Step-by-step explanation:

Given equation is $\log_x\left(8x-3\right)-\log_x\left(4\right)=2$

Now we need to solve that equation for x.

$\log_x\left(8x-3\right)-\log_x\left(4\right)=2$

Apply formula $\log_c\left(A\right)-\log_c\left(B\right)=\log_c\left(\frac{A}{B}\right)$

$\log_x\left(\frac{8x-3}{4}\right)=2$

Apply formula $\log_c\left(A\right)=b \Rightarrow c^b=A$

$x^2=\frac{8x-3}{4}$

$4x^2=8x-3$

$4x^2-8x+3=0$

$4x^2-2x-6x+3=0$

$2x(2x-1)-3(2x-1)=0$

$(2x-3)(2x-1)=0$

$2x-3=0$ or $2x-1=0$

$2x=3$ or $2x=1$

$x=\frac{3}{2}$ or $x=\frac{1}{2}$

Hence final answer is $\frac{3}{2}$ or $\frac{1}{2}$ .

6 0

3 years ago

Please help me asap!! Thank you

Setler79 [48]

-7z+42=-70
-7z= -112
z=16

4 0

3 years ago

Read 2 more answers