1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FrozenT [24]
3 years ago
7

Which of the following can not be guessed about the prehistoric organism by its fossil ?

Chemistry
1 answer:
Studentka2010 [4]3 years ago
4 0

Answer:

Evolution in the broadest sense explains that what we see today is different from what existed in the past. Galaxies, stars, the solar system, and earth have changed through time, and so has life on earth.Something that happened in the past is thus not "off limits" for scientific study. Hypotheses can be made about such phenomena, and these hypotheses can be tested and can lead to solid conclusions. Furthermore, many key aspects of evolution occur in relatively short periods that can be observed directly—such as the evolution in bacteria of resistance to antibiotics.Laws, like facts and theories, can change with better data. But theories do not develop into laws with the accumulation of evidence. Rather, theories are the goal of science.

Explanation:

You might be interested in
What mass of Ba3(PO4)2 is contained in 1575 mL of a 0.35M solution of Ba3(PO4)2
LekaFEV [45]

Answer:

= 331.81 g

Explanation:

Molarity is calculated by the formula;

Molarity = Moles/volume in liters

Therefore;

Moles = Molarity ×Volume in liters

          = 0.35 M × 1.575 L

          = 0.55125 Moles

But; Molar mass of Ba3(PO4)2 is 601.93 g/mol

Thus;

Mass = 0.55125 moles × 601.93 g/mol

         <u>=331.81 g</u>

7 0
4 years ago
A sample of a gas is occupying a 1500 ml container at a pressure of 3.4 atm and a temperature of 25 oc. if the temperature is in
Salsk061 [2.6K]

The new pressure will be 7.65 atm

<h3>General gas law</h3>

The problem is solved using the general gas equation:

P1V1/T1 = P2V2/T2

In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 ^O C, V2 = 2000 mL, and T2 = 75  ^O C

What we are looking for is P2.

Thus, P2 = P1V1T2/T1V2

          = 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm

More on general gas laws can be found here: brainly.com/question/2542293

#SPJ1

7 0
2 years ago
Answer?????????????????????????????!!?!?!?!,!?!?!?
aniked [119]

Answer:

why cant you just say the grasshopper eats the marsh grass the shrew eats the grasshopper and the hawk eats the shrew.

Explanation:

this makes sense to me but im not sure.

8 0
3 years ago
Read 2 more answers
What is the best explanation of a recessive gene
vodka [1.7K]

Answer:

come back

Explanation:

yeer

6 0
3 years ago
Read 2 more answers
Which of the following will most likely happen if the pancreas does not produce sufficient glucagon?
Zielflug [23.3K]
Answer: 1 Blood sugar will decrease because glucagon increased blood sugar when it falls too low
7 0
3 years ago
Other questions:
  • How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas
    8·1 answer
  • The reaction of sodium peroxide and water produces sodium hydroxide and oxygen gas. The following balanced chemical equation rep
    9·1 answer
  • 2. Natural neon exists as a mixture of 90.92% neon-20, 0.26% neon-21, and 8.82% neon-
    12·1 answer
  • Where is the protons and neutrons found
    8·2 answers
  • (a) Write the dissolution reaction for solid Na2CO3 below. (Use the lowest possible coefficients. Include states-of-matter under
    8·1 answer
  • Convert 4.0 kilometers 2 meters
    12·1 answer
  • My question today is : The reaction of 11.9g go CHCl3 with excess chlorine produced 10.2g of CCl4, carbon tetrachloride. What is
    15·1 answer
  • Compare the stability of primary, secondary and tertiary carbocation
    13·1 answer
  • What is the percent composition of acetaminophen (C8H9NO2).
    10·1 answer
  • What is infrared energy? simplify it
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!