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Ivanshal [37]
3 years ago
11

What mass of Ba3(PO4)2 is contained in 1575 mL of a 0.35M solution of Ba3(PO4)2

Chemistry
1 answer:
LekaFEV [45]3 years ago
7 0

Answer:

= 331.81 g

Explanation:

Molarity is calculated by the formula;

Molarity = Moles/volume in liters

Therefore;

Moles = Molarity ×Volume in liters

          = 0.35 M × 1.575 L

          = 0.55125 Moles

But; Molar mass of Ba3(PO4)2 is 601.93 g/mol

Thus;

Mass = 0.55125 moles × 601.93 g/mol

         <u>=331.81 g</u>

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swat32

Answer:

12 individuals are born 10 individuals emigrate, 4 individuals die, 14 individuals immigrate, 0 individuals are born

Explanation:

From the formula:

Population growth = (birth rate + immigration) – (death rate + emigration)

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<em>For the first option, b = 12, i = 0, d = 12, e = 12</em>

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<em>For the second option: b = 13, i = 0, d = 3, e = 16</em>

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<em>For the third option: b = 12, i = 20, d = 0, e = 8</em>

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population growth = (0+14) - (4+10) = 0

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