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telo118 [61]
3 years ago
10

Which of the following will most likely happen if the pancreas does not produce sufficient glucagon?

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
7 0
Answer: 1 Blood sugar will decrease because glucagon increased blood sugar when it falls too low
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Which of the fallowing scientific claims about the bond in the molecular compound HF is most likely to be true?
DENIUS [597]

The bond is highly polar is the scientific claim about the bond in the molecular compound HF is most likely to be true.

The term polar means that there is separation of charges, the bonds will be the more polar the greater the difference in electronegativity between the bonded atoms.

  • In hydrogen fluoride, for example, F is more electronegative than H because its nucleus, with 9 positive charges, attracts e-shares with H more strongly than the nucleus of H, with only one positive charge.

  • Therefore, the e- shared by covalence will be closer to F than to H and the molecule forms a permanent dipole.

Therefore, we can conclude that the bond is highly polar is the scientific claim about the bond in the molecular compound HF is most likely to be true.

Learn more here: brainly.com/question/6205088

6 0
3 years ago
How many molecules of co2 are in a 500. 0 ml container at 780 mm hg and 135°c? 8. 76 × 1021 molecules 9. 23 × 1021 molecules 5.
Aloiza [94]

<u>Step 1:</u>

ok we have to use the formula PV=nRT

p=Pressure (must be converted to atm)= 780 mmHg

1 amt= 760 mmHg use this as a conversion factor

780 mmHg (1 atm/760 mmHg)= 1.026

V= Volume= 5.00 mL = o.5 L

n=number of moles which we have to find first

R= 0.0821

T(convert to Kelvins by adding 273.15 to the celsius temperature)= 135 C + 273.15= 408.15 k

Now plug in->

(1.026 atm)(o.5 L)= n(0.0821)(408.15 K)

(1.026 atm)(0.5 L)= n(33.509115)

(0.513)= n(33.509115)

n(number of moles)= 0.01532 mol

Now we have to convert to moles using Avagodro's number which states that 1 mol = 6.022 x 10^23 molecules or atoms

So 0.01532 mol (6.022 x 10^23 number of molesules)/ (1 mol) = 9.225704 x 10^21 = 9.226 x 10^21 colecules

Step 2

You must transfer pressure into pascals, 780 mm Hg = 103991 Pa

135*C = 408.15 k

then from the equation pV = nRt

n = pV / RT (T in Kelvins, V in M^3)

n = 103991 x 500 x 10^-6 / (8.314 x 408.15)= 0.015322 moles of N2

1 mol of everything is 6.022 x 10^23 particles, so 0.15322 moles is 0.15322 x 6.022 x 10^23 = 9.2269084 x 10^21 molecules

Explanation:

Hope this helps :)

5 0
2 years ago
CHEM HELP!
sweet [91]

So let's convert this amount of mL to grams:

\frac{13.6g}{1mL}*1.2mL=16.32g

Then we need to convert to moles using the molar weight found on the periodic table for mercury (Hg):

\frac{1mole}{200.59g}*16.32g=8.135*10^{-2}mol

Then we need to convert moles to atoms using Avogadro's number:

\frac{6.022*10^{23}atoms}{1mole} *[8.135*10^{-2}mol]=4.90*10^{22}atoms

So now we know that in 1.2 mL of liquid mercury, there are 4.90*10^{22}atoms present.

4 0
4 years ago
C12H22O11 + 12O2 ---&gt; 12CO2 + 11H2O
boyakko [2]

Answer:

Oxygen is the limiting reactant.

Explanation:

Based on the reaction:

C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O

<em>1 mole of sucrose reacts with 12 moles of oxygen to produce 12 moles of CO₂ and 11 moles of H₂O.</em>

<em />

10.0g of sucrose (Molar mass: 342.3g /mol) are:

10.0g C₁₂H₂₂O₁₁ × (1mole / 342.3g) = 0.0292 moles of C₁₂H₂₂O₁₁

And moles of 10.0g of oxygen (Molar mass: 32g/mol) are:

10.0g O₂ × (1mole / 32g) = 0.3125 moles of O₂

For a complete reaction of 0.0292 moles of C₁₂H₂₂O₁₁ you need (knowing 12 moles of oxygen react per mole of sucrose):

0.0292 moles of C₁₂H₂₂O₁₁ × (12 moles O₂ / 1 mole C₁₂H₂₂O₁₁) = <em>0.3504 moles of O₂</em>

As you have just 0.3125 moles of O₂, <em>oxygen is the limiting reactant.</em>

8 0
4 years ago
You need to make 500 mL of a 3.40 M solution of sodium chloride. The only available solution is 1.5 M. Determine how to make the
vlabodo [156]

Answer:  (1.5 M) V1 = (3.40 M) (500mL)

            (multiply 3.40M x 500mL)    V1 = 1700 mL

1700 mL of the 1.5 M NaCl + 1200mL of water.

Explanation:

3 0
3 years ago
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