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Setler [38]
3 years ago
5

NAME DATE PERIOD 5-6 Practice 1 2 3 4 Probability and Odds Find the probability of each outcome if a pair of dice are rolled. Re

fer to the table below, which shows all of the possible outcomes when you roll a pair of dice. 4 5 6 (1, 1) (1, 2) (1, 3) (1. 4) (1,5) (1,6) 2 (2, 1) (2.2) (2, 3) (2, 4) (2,5) (2, 6) 3 (3, 1) (3, 2) (3, 3) (3, 4) (3,5) (3,6) 4 (4, 1) (4, 2) (4.3) (4, 4) (4, 5) (4, 6) 5 (5, 1) (5, 2) (5, 3) (5, 4) (5,5) (5, 6) 6 (6, 1) (6.2) (6.3) (6,4) (6,5) (6, 6) 1 36 1. ap h number on the second die . 2. a sum of 8 18 - ä 25 26 3. a sum of 7 4. load sum 5. a sum less than 6 6. a sum greater than 7 7. both die are the same number 8. a sum less than 2 0136 Find the odds of each outcome if a bag contains tīblue marbles, 3 yellow marbles, and 2 red marbles. 9. choosing a blue marble 10. choosing a red marble 7:5 11. choosing a yellow marble 1:5 5:7 12. choosing a yellow or red marble 5.7 13. choosing a yellow or blue marble 14. choosing a blue or red marble 15. not choosing a blue or red marble 16. not choosing a blue marble 5:7 222 Algebra: Concepts and Applications © Glencoe/McGraw-Hill​
Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer: Link to answer below

Step-by-step explanation:

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The formula for the volume of a rectangular prism is V = lwh. Which is the equivalent equation solved for h?​
wel

Answer:

V /(lw) = h

Step-by-step explanation:

V = lwh

Divide each side by lw

V/ ( lw) = lwh/(lw)

V /(lw) = h

4 0
2 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
2 years ago
The function f(x) = square root -x is shown on the graph. Which statement is correct?
EastWind [94]

Answer:

The Domain of the graph is all real numbers less than or equal to 0.


4 0
3 years ago
Read 2 more answers
How would i solve the math problem of x&gt;3
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I think any number mor than 3
6 0
3 years ago
James Harmon pays $850.80 per year for his life insurance. If Mr. Harmon were to pay the premiums monthly, the payments would be
Deffense [45]

Answer:

8.0%

Step-by-step explanation:

We have been given that James Harmon pays $850.80 per year for his life insurance. If Mr. Harmon were to pay the premiums monthly, the payments would be $76.57.

First of all, we will find the amount paid for the year using the monthly rate by multiplying $76.57 by 12 (1 year = 12 months).

\text{Amount paid for the year using the monthly rate}=\$76.57\times 12

\text{Amount paid for the year using the monthly rate}=\$918.84

Now, we will use percent change formula.

\text{Percent change}=\frac{\text{Final value}-\text{Initial value}}{\text{Initial value}}\times 100

\text{Percent change}=\frac{\$918.84-\$850.80}{\$850.80}\times 100

\text{Percent change}=\frac{\$68.04}{\$850.80}\times 100

\text{Percent change}=0.0799717912552891\times 100

\text{Percent change}=7.99717912552891\%

\text{Percent change}\approx 8.0\%

Therefore, Mr. Harmon is paying 8.0% more for the year using the monthly rate.

3 0
3 years ago
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