First i'd recommend rearranging the equation into slope-intercept form
so it's easier to conceptualize cuz you can see the slope and
y-intercept of its graph. Then make a table and plug a range of x's into the equation to get a y coordinate. When you have all of the ordered pairs, just plot them and draw a line through them and you're done.
3x-6y=-3 x | y
-6y=-3-3 -4 -1.5
y=(1/2)x+(1/2) -3 -1
^ ^ -2 -.5
slope y-intercept -1 0
0 .5
1 1
2 1.5
3 2
Here, the union tells us that at least one of the original inequalities must be true. We solve each separately, first.
x + 2 < 5 OR x - 7 > -6
x < 3 OR x - 7 > -6 subtract 2 on both sides of the equation left of the OR
x < 3 OR x > 1 add 7 on both sides of the equation right of the OR
Thus x < 3 or x > 1. In set notation, {x | x < 3 or x > 1} is true.
Answer:
8.71
Step-by-step explanation:
(-5.2)-(-6.01)+7
Subtracting a negative is like adding
(-5.2)+(6.01)+7
Subtract 5.2 from 6.01
.81+7
Add .61 to 7
7.81
Answer:
See below.
Step-by-step explanation:
This is the formula for the value of an investment with compound interest.
PO is the initial amount invested, P is the amount after investing t years , r is yearly rate of interest (as a fraction) and n is the number of times interest is paid per year.
An example using values will serve to explain it further. If the rate is 2% ( which = 0.02) per year and the interest is added to the account every 6 months ( twice a year) then, in the parentheses we have ( 1 + 0.02/2). The 1 is there because we are talking about the amount of money PLUS the interest. Now if we are dealing with 5 year's investment , the exponent nt will be 2*5 = 10 because the interest is paid 2 times a year over 5 years: - 10 payments. So if we invest 10,000 at 2% interest over 5 years with 2 interest payments a year the total after 5 years = P = 10,000(1 + 0.02/2)^10 = 11,046.22.