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2 years ago

A number is chosen at random from 1 to 25. find the probability of selecting a number less than 3?

1 answer:

8 0

Answer: Because we are finding the probability of selecting a number less than three, you are left with two options. The answer would be either one, or two.

If you were to also use three it wouldn´t be correct because three is equivalent to three.

Step-by-step explanation:

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The quotient below is shown without the decimal point. Use number sense to place the decimal point correctly.

katrin2010 [14]

Answer:

35.8

Step-by-step explanation:

$\frac{340.1}{9.5}$ = 358

We know that our answer can never be greater than 358 since the dividend

is 340.1 and the divisor is 9.5;

Also,

Both values are to one decimal places and we can use this to solve the problem;

9 can divide 340 in about 37 place with a remainder of 7,

So, it is appropriate to make the solution 35.8

5 0

2 years ago

What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

PIT_PIT [208]

9514 1404 393

Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

3 0

2 years ago

Find the value of x.<br> 105°/15x

Natalija [7]

$\text{The two angles are supplementary, so their measures add up to 180 degrees.}$

$~~~~~~15x+105 = 180\\\\\implies 15x = 180 -105\\\\\implies 15x = 75\\\\\implies x =\dfrac{75}{15}\\\\\implies x = 5$

8 0

1 year ago

One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al

Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

First Sunday, a=1
Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

$\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18$

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

$\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089$

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0

2 years ago

What is the image of the point (6,-9) after a dilation with k = 3

saveliy_v [14]

Answer:

Step-by-step explanation:

6 0

2 years ago

A number is chosen at random from 1 to 25. find the probability of selecting a number less than 3?​

A number is chosen at random from 1 to 25. find the probability of selecting a number less than 3?