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3 years ago

What would you fill in the blank to make the equation have no solution? -2+4x+6=3x+5__?

Mathematics

1 answer:

Fed [463]3 years ago

6 0

Answer:

Step-by-step explanation:

-2

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If the spin rate of the CD is 580 rpm what distance is traveled by the piece of dust (in radians) in 2.9 mins

natta225 [31]

Answer:

$d=10568.76rads$

Step-by-step explanation:

From the question we are told that:

Angular Velocity $\omega=580rpm=>60.74rads/sec$

Time $t=2.9mins=>174sec$

Generally the equation for distance d is mathematically given by

$d=\omega*t$

$d=60.74*174$

$d=10568.76rads$

7 0

3 years ago

Chase caught 2/3 of the balls hit to left field. Ryan caught 3/5 of the balls hit to right field. Which pair of equivalent fract

slava [35]

Answer:

1 4/15 balls

Step-by-step explanation:

From the question, we are told that:

Chase caught 2/3 of the balls hit to left field.

Ryan caught 3/5 of the balls hit to right field.

The Lowest common denominator for both fraction is given as 15

Hence, the equivalent fractions for each boy is calculated such that the denominators of both fraction is 15

For Chase:

We Multiply both numerator and Denominator by 5

2 × 5 /3 × 5 = 10/15

2/5 = 10/15

For Ryan

We Multiply both numerator and Denominator by 3

3 × 3 /5 × 3 = 9/15

3/5 = 9/15

The total amount of the balls they both caught is:

10/15 + 9/15

= 19/15 = 1 4/15

8 0

3 years ago

At the city museum, child admission is $6.60 and adult admission is $9.80. On Tuesday, four times as many adult tickets as child

Svet_ta [14]

See photo for solutions

8 0

3 years ago

A standard deck of cards contains 52 cards. One card is selected from the deck.(a)Compute the probability of randomly selecting

Aneli [31]

a. There are four 5s that can be drawn, and $\binom43=4$ ways of drawing any three of them. There are $\binom{52}3=22,100$ ways of drawing any three cards from the deck. So the probability of drawing three 5s is

$\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018$

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of $\frac8{52}=\frac2{13}\approx0.15$ of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability $\frac{12}{52}=\frac3{13}\approx0.23$ of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of $\frac{16}{52}=\frac4{13}\approx0.31$ .