The total side to side distance at the top of the building, covered during such an oscillation is 8.4 cm.
Solution:
The height of building is, h = 152 m.
The frequency on windy days is, f = 0.17 Hz.
The acceleration on the top of building is, a = 2/100g (Here g is gravitational acceleration).



A = 0.042m
hence the total distance is twice the distance
that is 0.084m
<h3>
What is oscillation?</h3>
- The recurrent or periodic change of a quantity around a central value (often an equilibrium point) or between two or more different states is known as oscillation.
- Alternating current and a swinging pendulum are two common examples of oscillation. Physics can employ oscillations to approximate complicated interactions, like those between atoms.
To learn more about Oscillation with the given link
brainly.com/question/17133973
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Question:
The New England Merchants Bank Building in Boston is 152 m high. On windy days it sways with a frequency of 0.17 Hz, and the acceleration of the top of the building can reach 2.0% of the free-fall acceleration, enough to cause discomfort for occupants. What is the total distance, side to side, that the top of the building moves during such an oscillation?
Formula for momentum is mass times velocity so you do 52 kg times 5 m/s and that equals 260 kg x m/s
Protons and neutrons are held together
Answer:
F=1.4384×10⁻¹⁹N
Explanation:
Given Data
Charge q= -8.00×10⁻¹⁷C
Distance r=2.00 cm=0.02 m
To find
Electrostatic force
Solution
The electrostatic force between between them can be calculated from Coulombs law as

Substitute the given values we get
