A model airplane has momentum given by p=[(-0.75kg.m/s3)t2 + (3.0kg.m/s)] i + (0.25kg.m/s2)t j. Find the components Fx, Fy, and
1 answer:
Answer:
= -1.5t
= 0.25
= 0
Explanation:
Given equation;
p = [(-0.75 kgm/s³)t² + (3.0 kgm/s)] i + (0.25 kgm/s²)t j.
From Newton's law, the rate of change of momentum of a body is the net force acting on that body. i.e
∑F = -----------(i)
Substitute the equation of p into equation (i) and differentiate with respect to t as follows;
∑F = =
∑F = =
∑F =
But
∑F =
Where;
are the components of the net force in the x, y and z direction respectively.
=> =
=
=> = -1.5t
=> = 0.25
=> = 0
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Answer:
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Explanation:
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Generally from the law of energy conservation we have that
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And is the change in electric potential energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
Here is zero because the electric potential energy at the initial stage is zero so
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Generally considering from initial position to a position of distance from the nucleus
Here represented the distance of the proton from the nucleus where the velocity is
Generally from the law of energy conservation we have that
Here is the change in kinetic energy from initial position to a position of distance R from the nucleus , this is mathematically represented as
=>
=>
=>
And is the change in electric potential energy from initial position to a position of distance
from the nucleus , this is mathematically represented as
Here is zero because the electric potential energy at the initial stage is zero so
So
=>
=>
Divide equation 2 by equation 1
=>
=>
=>