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4 years ago

Which vector best represents the net force acting on +3C charge in the diagram?

Physics

2 answers:

VMariaS [17]4 years ago

8 0

-- The two negative charges both attract the positive charge at the origin.

-- The -4C charges are horizontally symmetrical, so there's no net horizontal force on the +3C at the origin.

-- However, the -4C both pull it down.

-- So the net force on the +3C at the origin is directed straight down.

The arrow labelled <em>' C '</em> represents the net force on it.

Zigmanuir [339]4 years ago

7 0

Answer:

Choice C I got it correct on the assignment.

Explanation:

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Answer:

The charge in each ball will be 3 * 10^-12 C

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(Assuming the correct charge of the second ball is 8 * 10^-12)

When the balls are brought in contact, all the charges are split evenly among then.

So first we need to find the total charge combined:

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3 years ago

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Answer:

0.087 m

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the formula for the time period of the pendulum is given by

$T = 2\pi \sqrt{\frac{I}{mgd}}$ .... (1)

where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.

Moment of inertia of the rod about the centre of mass, Ic = mL²/12

By using the parallel axis theorem, the moment of inertia of the rod about the pivot is

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Substituting the values in equation (1)

$3 = 2 \pi \sqrt{\frac{\frac{mL^{2}}{12}+ md^{2}}{mgd}}$

$9=4\pi^{2}\times \left ( \frac{\frac{L^{2}}{12}+d^{2}}{gd} \right )$

12d² -26.84 d + 2.25 = 0

$d=\frac{26.84\pm \sqrt{26.84^{2}-4\times 12\times 2.25}}{24}$

$d=\frac{26.84\pm 24.75}{24}$

d = 2.15 m , 0.087 m

d cannot be more than L/2, so the value of d is 0.087 m.

Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.

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