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Question:
Howard is designing a chair swing ride. The swing ropes are 4 meters long, and in full swing they tilt in an angle of 23°. Howard wants the chairs to be 3.5 meters above the ground in full swing. How tall should the pole of the swing ride be? Round your final answer to the nearest hundredth.
Answer:
7.18 meters
Step-by-step explanation:
Given:
Length of rope, L = 4 m
Angle = 23°
Height of chair, H= 3.5 m
In this question, we are to asked to find the height of the pole of the swing ride.
Let X represent the height of the pole of the swing ride.
Let's first find the length of pole from the top of the swing ride. Thus, we have:
Substituting figures, we have:
Let's make h subject of the formula.
The length of pole from the top of the swing ride is 3.68 meters
To find the height of the pole of the swing ride, we have:
X = h + H
X = 3.68 + 3.5
X = 7.18
Height of the pole of the swing ride is 7.18 meters
Answer: y = 2x+22
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Explanation:
The equation y = 2x+5 is in the form y = mx+b
m = 2 = slope
b = 5 = y intercept
Parallel lines have equal slopes, but different y intercepts. So the answer will be in the form y = 2x+c, where b and c are different numbers. Since b = 5, this means c must be some other number. If c = 5, then we'd have the exact same line.
Let's plug in (x,y) = (-5,12), along with the slope m = 2, and solve for c
y = mx+c
12 = 2(-5)+c
12 = -10+c
12+10 = c
22 = c
c = 22
Since m = 2 and c = 22, we go from y = mx+c to y = 2x+22
The equation of the parallel line is y = 2x+22
The graph is below.
