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2 years ago

in grammatically correct sentences, trace the large of the products of photosynthesis as they exit the leaf

Biology

1 answer:

vladimir1956 [14]2 years ago

5 0

Answer:

yes

Explanation:

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Arrange the layers and faults from oldest to youngest.

Lera25 [3.4K]

What layers and faults??

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2 years ago

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Honey vs Sugar which is healthier and why?

Blizzard [7]

Honey has more calories than sugar, so sugar is healthier

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3 years ago

1.This method of reforestation is done by natural means with the aid of the wind,birds,rodents and running water which scatters

ANEK [815]

Answer:

T. Natural Reseeding.
D. Species Diversity
A. Ecosystem Diversity.

Explanation:

Natural reseeding uses natural elements and actors to plant the seeds of trees. These elements and actors include water, wind, birds, rodents and other actors capable of scattering seed.

Species diversity is what defines the differentiation between the different species in an ecosystem and Ecosystem diversity relates to how biological communities/ ecosystems can be different from each other based on the organisms and food chains available in each.

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3 years ago

The prime mover of the elbow extension is the

mote1985 [20]

Answer:

triceps brachii muscle

The prime mover of elbow extension is the triceps brachii muscle, and is assisted by the much smaller anconeus muscle. All anterior (front) arm muscles cause elbow flexion. These muscles are the biceps brachii, brachialis and brachioradialis.

Explanation:

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3 0

3 years ago

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scalloped (sd) is an X-linked recessive and ebony (e) is an autosomal recessive mutation. What proportion of scalloped, ebony fe

alisha [4.7K]

Answer:

1/16

Explanation:

scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
ebony (e) is an autosomal mutation recessive to e+ (wild type).

The two genes are independent because they are located on different chromosomes.

<h3>Parental generation:</h3>

True breeding scalloped female wild type for ebony (Xsd Xsd e+e+) mates with a true breeding male mutant only for ebony (Xsd+ Y ee).

The female only produces Xsd e+ gametes. The male produces Xsd+ e or Y e gametes. Therefore, the F1 females will have the genotype Xsd Xsd+ e e+ and the F1 males will have the genotype Xsd Y e e+.

If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a Xsd Xsd e e genotype and appear in a 1/16 proportion.

6 0

3 years ago