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Serggg [28]
3 years ago
8

Pllllllllllllllllllssssssssss help me will give brainiest if correct

Physics
2 answers:
Gelneren [198K]3 years ago
8 0

Answer:

I believe it is the same as before-Electrical energy is transformed into heat and light energy.

Explanation:

Hope this helps'-'

const2013 [10]3 years ago
7 0

Chemical energy (in his muscles) ===> kinetic energy ===> electrical energy ===> light energy and a little bit of heat energy

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There are uniform cubes in a toy box, a child makes a pillar using these cubes on a rough plane which is inclined to the horizon
earnstyle [38]

The maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

<h3>Net force on the box</h3>

The net force on the box can be used to determine the maximum number of cubes that can be stacked without sliding.

The stack cubes must be at equilibrium.

∑Fx = 0

nW - μFₙ = 0

where;

  • n is number of the cubes
  • Fₙ is the normal force of the cubes
  • W is the weight of the cubes acting parallel to the plane

n(mg)sinθ - μmgcosθ = 0

n(mg)sinθ  = μmgcosθ

nsinθ  = μcosθ

  • let the coefficient of friction = 1

nsinθ  = cosθ

n = cosθ/sinθ

n = 1/tanθ

n = (1)/(1/8)

n = 8

Thus, the maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

Learn more about cubes here: brainly.com/question/1972490

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7 0
2 years ago
The figure shows an overhead view of a ring that can rotate about its center like a merry-go-round. Its outer radius R2 is 0.8 m
Shtirlitz [24]

The cat increase the kinetic energy of the cat-ring system is  42.4 J.

Mass of the merry-go-round = M = 7.6 kg

Outer radius of the merry-go-round = R2 = 0.9 m

Inner radius of the merry-go-round = R1 = R2/2 = 0.9/2 = 0.45 m

Moment of inertia of the merry-go-round = I

I = 3.8475 kg.m2

Mass of the cat = m = M/4 = 7.6/4 = 1.9 kg

Initially the cat is sitting at the outer edge that is at a distance of 'R2' from the center.

Initial moment of inertia of the system = I1

I1 = I + mR22

I1 = 3.8475 + (1.9)(0.9)2

I1 = 5.3865 kg.m2

Initial angular speed of the system =  title=View image!

1 = 7.6 rad/s

Now the cat walks to the inner edge of the merry-go-round therefore it is at a distance 'R1' from the center.

New moment of inertia of the system = I2

I2 = I + mR12

I2 = 3.8475 + (1.9)(0.45)2

I2 = 4.23225 kg.m2

New angular speed of the system =

I = I2

(5.3865)(7.6) = (4.23225)2

= 9.673 rad/s

Initial kinetic energy of the system = E1

E2 = 198 J

Amount by which the kinetic energy of the system increases =

E = E2- E1

title=View image!

E = 198 - 155.6

ΔE = 42.4 J

Amount by which the kinetic energy of the system increases when the cat crawls to the inner edge = 42.4 J.

Kinetic Energy:

Kinetic energy is the energy that an object possesses due to its motion. It is defined as the work required to accelerate an object of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.

Learn about Kinetic Energy here:

brainly.com/question/25959744

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3 0
1 year ago
A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this
kondaur [170]

Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

\lambda = \dfrac{v}{f}

\lambda = \dfrac{402}{603}

\lambda = 0.67\ m

Number of anti nodes in the standing wave

n=\dfrac{l}{\frac{\lambda}{2}}

n=\dfrac{2l}{\lambda}

n=\dfrac{2\times 1.33}{0.67}

n =3.97= 4.

Number of antinodes is equal to 4.

7 0
3 years ago
A 750 watt hairdryer is used for 60 seconds. how many joules of energy are used?
daser333 [38]
We know, Power = Energy / time
Here, P = 750 Watt
t = 60 sec

Substitute their values, 
750 = E / 60
E = 750 * 60
E = 45,000 J

In short, Your Answer would be 45,000 Joules

Hope this helps!
4 0
4 years ago
Read 2 more answers
what do radio waves transfer between a cell phone and a cell phone tower? A.Sound. B.Energy. C. the medium D. air particles
sergeinik [125]
The answer would be energy, because all wave emitters give off at least one type of energy....
8 0
4 years ago
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