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Scorpion4ik [409]
3 years ago
6

Help me plzzzAnd thank u​

Physics
1 answer:
GuDViN [60]3 years ago
5 0

Answer:

$ 1.1

Explanation:

From the question given above, the following data were obtained:

Cost per kWh = $ 0.1

Current (I) = 10 A

Voltage (V) = 220 V

Time (t) = 5 h

Cost of operation =?

Next, we shall determine the power the electric oven. This can be obtained as follow:

Current (I) = 10 A

Voltage = 220 V

Power (P) =?

P = IV

P = 10 × 220

P = 2200 W

Next, we shall convert 2200 W to KW. This can be obtained as follow:

1000 W = 1 KW

Therefore,

2200 W = 2200 W × 1 KW / 1000 W

2200 W = 2.2 KW

Thus, 2200 W is equivalent to 2.2 KW.

Next, we shall determine the energy consumed by the electric oven. This can be obtained as follow:

Power (P) = 2.2 KW

Time (t) = 5 h

Energy (E) =?

E = Pt

E = 2.2 × 5

E = 11 KWh

Finally, we shall determine the cost of operation. This can be obtained as follow:

1 KWh cost $ 0.1

Therefore,

11 KWh will cost = 11 × 0.1

11 KWh will cost = $ 1.1

Therefore, the cost of operating the electric oven is $ 1.1

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<h3>Answer:</h3>

1.3 Amps

<h3>Explanation:</h3>

<u>We are given;</u>

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We are required to calculate the current in the circuit.

<h3>Step 1: We need to find the effective resistance.</h3>

When resistors are arranged in series, the effective resistance is calculated by;

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Therefore;

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<h3>Step 2: Calculate the current in the circuit</h3>

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