B, Because the classroom started with cylinder cups they should add 7mL into the cup and then transfer the 7mL on the cups
pKa is a value which is related to the acid dissociation constant Ka
pKa = -log Ka
i.e. Ka = 10^-pKa
The deprotonation reaction of acetylene is:
HC≡CH ↔ HC≡C⁻ + H⁺
pKa (HC≡CH) = 25
Solvents with pKa greater than 25 will deprotonate acetylene.
Ans: CH2=CH⁻ pka = 44 and CH3NH⁻ pka = 40
Answer:
Density = 4.06 * 10^14
Explanation:
Givens
r = 1 * 10^-13 cm
m = 1.7 * 10^-24 grams
Formula
V = 4/3 * pi * r^3
D = m/V
Solution
Put the givens into the formula.
V = (4/3) 3.14 * (1 * 10^-13)^3 Find the value for r^3
V = (4/3) 3.14 * 1 * 10^-39 Find the volume. Indicate divide by 3
V = 1.256 10^-38/3
V = 4.1867 * 10^-39
Density = m / v
Density = 1.7*10^-24/4.1867*10^-39 Do the division
Density = .406 * 10^(-24 + 39)
Density = .406 * 10^15 grams/ cm^3
Answer: Density = 4.06 * 10^14
34 is the answer i htink sorry if its wrong
Answer:
B. →
Explanation:
This sign is used to show that the reactants yield the products, which also separates the two. Hope this helps and good luck on your assigment.
