I am a little confused
2 answers:
You might be interested in
Answer:
<u>K.E. = 5.4362 × 10⁻¹⁹ J</u>
Explanation:
The expression for Bohr velocity is:
Applying values for hydrogen atom,
Z = 1
Mass of the electron () is 9.1093×10⁻³¹ kg
Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C
= 8.854×10⁻¹² C² N⁻¹ m⁻²
h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s
We get that:
Given, n = 2
So,
Kinetic energy is:
So,
<u>K.E. = 5.4362 × 10⁻¹⁹ J</u>
The central Xe atom in XeO3 has three bonding domains and one lone pair of electrons. Hence, the electron geometry is tetrahedral and molecular geometry is pyramidal.
