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Eddi Din [679]
3 years ago
14

What is name of each shape​

Chemistry
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

I am so sorry I do not know this

Explanation:

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Determine the oh of a solution that is 0.220 m in hco3
ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

Explanation :

As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

As, 1 mole of HCO_3^- dissociates to give 1 mole of hydrogen ion (H^+)

Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

Now we have to calculate the hydroxide ion concentration.

As we know that:

[H^+][OH^-]=1\times 10^{-14}

0.200\times [OH^-]=1\times 10^{-14}

[OH^-]=5\times 10^{-14}

Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

6 0
4 years ago
What is the volume in a 2. 00M solution containing 8.00 moles of solute?
MrMuchimi

Answer:

4000cm³

Explanation:

2.0moles-1000cm³

8.0moles-?

(8.0×1000)÷2

=4000cm³

5 0
3 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

\frac{dA}{dt}= kA

\Rightarrow \frac{dA}{A}=kdt

Integrating both sides

ln A= kt+c₁

\Rightarrow A= e^{kt+c_1}

\Rightarrow A=Ce^{kt}         [e^{c_1}=C]

The initial condition is A(0)= A₀,

\therefore A_0=Ce^{0.k}

\Rightarrow C=A_0

\therefore A=A_0e^{kt}.........(1)

Given that the Pb_{209}  has half life of 3.3 hours.

For half life A=\frac12 A_0 putting this in equation (1)

\frac12A_0=A_0e^{k\times3.3}

\Rightarrow ln(\frac12)= 3.3k     [taking ln both sides, ln \ e^a=a]

\Rightarrow k=\frac{ln \frac12}{3.3}

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

\therefore 0.2=1e^{(-0.21)\times t}

\Rightarrow e^{-0.21t}=0.2

\Rightarrow -0.21t= ln(0. 2)

\Rightarrow t= \frac{ln (0.2)}{-0.21}

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

3 0
3 years ago
What do these two changes have in common sauce burning on a stove and jewelry tarnishing
Andrews [41]

The changes that are common between sauce burning on a stove, and jewelry tarnishing, which is a chemical change.

How to define chemical and physical changes?

Chemical Change-

Any alteration that produces new chemical substances with distinct properties is considered a chemical change. Chemical reactions involve the rearrangement and recombination of elements and compounds to create new substances. Examples of chemical changes are listed below:

  • Burning
  • Digestion
  • chemicals changing colors
  • Tarnishing
  • compost rotting

Physical Change-

A substance is not destroyed or transformed into something new by physical changes. A substance can undergo physical changes that alter its shape, size, or phase. The constituents of an element or compound do not change during a physical change. Examples of physical changes are listed below:

  • Boiling water
  • Chopping, Cutting, Carving
  • Evaporation
  • Freezing, Melting, Condensation

To know more about chemical and physical changes, visit the given link:

brainly.com/question/20628019

#SPJ4

5 0
1 year ago
The amount of oxygen bound to hemoglobin _____.
Luba_88 [7]
The amount of oxygen bound to hemoglobin is 98.5% 
7 0
3 years ago
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