Give three examples of heterogeneous mixtures and three examples of solutions that you might use in everyday life.
1 answer:
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448 K is the final temperature of the water.
<h3>What is specific heat capacity?</h3>The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Given,
the mass of Na is 23 g
The volume of water = 293 cm3
Mass of water = 293 g
Total solution mass = 23 g + 293 g = 316 g
Specific heat capacity of water = 4.18 J/Kg
The equation relating mass, heat, specific heat capacity and temperature change is:
q = mcΔT
197 kJ = 316 g x 4.18 J/Kg x ()
197 kJ = 316 g x 4.18 J/Kg x ( -298 K)
0.1491429956 x 1000 = -298 K
149.1429956 + 298 =
447.1429956 =
448 K =
Hence, 448 K is the final temperature of the water.
<h3>What does a high specific heat capacity mean?</h3>A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.
Learn more about specific heat capacity here:
#SPJ4
Answer:
2.42L
Explanation:
Given parameters:
V₁ = 1.8L
T₁ = 293K
P₁ = 101.3kPa
P₂ = 67.6kPa
T₂ = 263K
Unknown:
V₂ = ?
Solution:
To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;
All the units are in the appropriate form. We just substitute and solve for the unknown;
101.3 x 1.8 / 293 = 67.6 x V₂ / 263
V₂ = 2.42L