Answer:
(-1-√33)/2, (-1+√33)/2
Step-by-step explanation:
If one of them is x, then it satisfies ...
x + -8/x = -1
x^2 -8 = -x . . . . . multiply by x
x^2 +x = 8 . . . . . add x+8
x^2 +x + 1/4 = 8+1/4 . . . . complete the square
(x +1/2)^2 = 33/4
x + 1/2 = ±(1/2)√33 . . . . . . take the square root
x = (-1/2)(1 ± √33) . . . . . . . subtract 1/2
The numbers are approximately ...
-3.37228, 2.37228
Answer:
80 cm²
Step-by-step explanation:
Trapezoid LPKB has area ...
A = (1/2)(b1 +b2)h = (1/2)(4 +20)(20) = 240 . . . . cm²
Triangle BPN has area ...
A = (1/2)bh = (1/2)(20)(20) = 200 . . . . cm²
Triangle BKN has a height that is 4/5 the height of triangle BPN, so will have 4/5 the area:
ΔBKN = (4/5)(200 cm²) = 160 cm²
The area of quadrilateral LPKB is that of trapezoid LPNB less the area of triangle BKN, so is ...
240 cm² - 160 cm² = 80 cm²
Answer: 11
Step-by-step explanation:
2 times 11 is 22. 22-8=14
base 16y^2
height y^2 + y + 3
V = b*h
V = 16y^2(y^2 + y + 3)
V = 16y^4 + 16y^3 + 48y^2
Last option